JavaFX应用程序线程如何工作？ [英] How JavaFX application thread works?

问题描述

我遇到了Java FX应用程序线程的问题。这是一个伪代码：

I have a problem with Java FX application thread. Here is a pseudo-code:

showMenu();
//Contoller which waits for action(pressing button)...
showLoadingPic();
Thread.sleep(2000);
showMap();

问题是睡眠发生在showMenu（）中显示的窗口中，showLoadingPic（）是完全没有显示，并且在showMap（）的结束窗口显示。

The problem is that the sleep occurs in window which is displayed in showMenu(), showLoadingPic() is not shown at all, and at the end window in showMap() is shown.

showLoadingPic中的场景有一个进度条，运行2秒，这与了Thread.sleep（2000）。

The scene in showLoadingPic has a progress bar which runs 2 secs which is the same time as Thread.sleep(2000).

所以看起来javafx应用程序线程块showLoadingPic（）和showLoadingPic（）在后台运行。

So it seems like javafx application thread blocks showLoadingPic() and showLoadingPic() runs at background.

有人可以帮我解决这个问题吗？

Can somebody help me to fix this??

提前谢谢你！

推荐答案

有一个Java FX事件调度线程，它处理所有与GUI相关的任务。您必须更新此线程中的所有UI组件。
长时间运行的任务，比如 Thread.sleep 永远不应该在这个线程中执行，因为windows会挂起，GUI将冻结。

There is a Java FX event dispatch thread, which handle all GUI-related tasks. You must update all UI components in this thread. Long-running tasks, like Thread.sleep should never be executed in this thread, since windows will hang, and the GUI will be frozen.

执行应用程序主线程中的所有代码，并通过调用 Platform.runLater 。

Execute all your code in the application main thread, and perform only GUI tasks in JavaFX thread, by calling Platform.runLater.

有关此主题的参考资料：

References on this topic:

• JavaFX中的并发，来自Oracle


• 相关SO问题

• Concurrency in JavaFX, from Oracle
• Related SO question

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