JavaFX可以从TabContent（节点）访问Tab或TabPane [英] JavaFX get access to a Tab or TabPane from a TabContent(Node)

问题描述

有没有办法获得 Tab 或 TabPane 的引用，如果您参考了选项卡中只有节点，例如

Is there a way to get a reference to Tab or TabPane without no improvised way if you have reference to only the Node inside the Tab for eg

TabPane tabPane = new TabPane();
Tab tab = new Tab();
tab.setText("new tab");
Rectangle drect = new Rectangle(200,200, Color.LIGHTSTEELBLUE);
tab.setContent(drect);
tabPane.getTabs().addAll(tab,new Tab("tab 2"));

假设我只引用 drect 如何我可以获得标签。
我对 Node.setUserData（）也不感兴趣 drect.getParent（）。getClass（）。getName（）返回
TabPaneSkin anon内部类 TabContentRegion ：两个陌生人。

assume i only have reference to drect how can i get tab. I am not interested in Node.setUserData() also drect.getParent().getClass().getName() returns TabPaneSkin anon inner class TabContentRegion: two strangers.

我想说的是 Node.getParent（）应该返回父节点，一般单知识（ 节点在场景图中的表示可以使用getParent（） ）进行跟踪，但是，当涉及到标签 s全部错误，因此我的问题

All i am trying to say is Node.getParent() should return the parent Node , general uni-knowledge ( node's representation in the scene graph can be traced with getParent() ), but, when it comes to Tabs its all wrong, hence my question

编辑

为什么我需要这个，假设你有 TabPane 包含太多 Tab ，在一个特定的标签中，你有 TreeView s作为其节点内容从某些条件中选择，对于特定的 TreeView ，您有不同的自定义 Cell s，因为它的 TreeItem 在UI和f方面有所不同类似于更改样式绑定字体&其他绑定和动画选项卡隐藏 TabPane中的其他选项卡 ，关闭其他标签 s

Why i needed this, suppose you have TabPane consisting of soo many Tab, in one particular Tab you have a TreeViews as its Node-Content which is selected out of some conditions, and for that particular TreeView you have different Custom Cells because its TreeItems differ in UI and function- like changing styles binding Fonts& other bindables and Animating Tab hiding other Tabs in the TabPane, closing other Tabs

这种方法遵循这种方法对我来说似乎是合法的，你不做不必要的东西，比如让孩子暴露在恶劣的天气里。 :-)

with this scenario following this approach seems legit for me as, you do not do unnecessary stuff, like exposing children to bad weather. :-)

谢谢Sir James_D

Thanks Sir James_D

推荐答案

Tab 本身不是节点，因此您无法通过以任何方式迭代场景图来获取选项卡。如果你在层次结构中走得足够远，你可以进入 TabPane 。例如：

The Tab itself is not a Node, so you can't get the tab just by iterating through the scene graph in any way. You can get to the TabPane if you go up far enough in the hierarchy. For example:

private TabPane findTabPaneForNode(Node node) {
    TabPane tabPane = null ;

    for (Node n = node.getParent(); n != null && tabPane == null; n = n.getParent()) {
        if (n instanceof TabPane) {
            tabPane = (TabPane) n;
        }
    }

    return tabPane ;
}

将返回最近的 TabPane 包含传入的节点，如果节点不在选项卡窗格中，则 null 。

will return the nearest TabPane containing the node passed in, or null if the node is not in a tab pane.

但是，需要这个似乎是你的设计错了。如果您在选项卡窗格中放置一个节点，则在某些时候创建一个选项卡，因此您应该只组织代码，以便可以使用该选项卡的引用。

However, needing this just seems like your design is wrong. If you put a node in a tab pane, at some point you create a tab, so you should just organize your code so you have the reference to the tab available.

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