JSON.stringify，避免TypeError：将循环结构转换为JSON [英] JSON.stringify, avoid TypeError: Converting circular structure to JSON

问题描述

我有一个大对象，我想转换为JSON并发送。但它具有圆形结构。我想抛出任何存在的循环引用并发送任何可以进行字符串化的内容。我该怎么做？

I have a big object I want to convert to JSON and send. However it has circular structure. I want to toss whatever circular references exist and send whatever can be stringified. How do I do that?

谢谢。

var obj = {
  a: "foo",
  b: obj
}

我想将obj字符串化为：

I want to stringify obj into:

{"a":"foo"}

推荐答案

使用 JSON.stringify 与自定义替代品。例如：

Use JSON.stringify with a custom replacer. For example:

// Demo: Circular reference
var o = {};
o.o = o;

// Note: cache should not be re-used by repeated calls to JSON.stringify.
var cache = [];
JSON.stringify(o, function(key, value) {
    if (typeof value === 'object' && value !== null) {
        if (cache.indexOf(value) !== -1) {
            // Duplicate reference found
            try {
                // If this value does not reference a parent it can be deduped
                return JSON.parse(JSON.stringify(value));
            } catch (error) {
                // discard key if value cannot be deduped
                return;
            }
        }
        // Store value in our collection
        cache.push(value);
    }
    return value;
});
cache = null; // Enable garbage collection

此示例中的替换器不是100％正确（取决于您的定义） 重复）。在以下情况中，将丢弃一个值：

The replacer in this example is not 100% correct (depending on your definition of "duplicate"). In the following case, a value is discarded:

var a = {b:1}
var o = {};
o.one = a;
o.two = a;
// one and two point to the same object, but two is discarded:
JSON.stringify(o, ...);

但概念是：使用自定义替换器，并跟踪解析的对象值。

But the concept stands: Use a custom replacer, and keep track of the parsed object values.

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