如果不存在Array.push（）？ [英] Array.push() if does not exist?

问题描述

如果两个值都不存在，我怎样才能进入数组？这是我的数组：

How can I push into an array if neither values exist? Here is my array:

[
    { name: "tom", text: "tasty" },
    { name: "tom", text: "tasty" },
    { name: "tom", text: "tasty" },
    { name: "tom", text: "tasty" },
    { name: "tom", text: "tasty" }
]

如果我尝试使用名称再次推入数组：tom或 text：tasty，我不希望发生任何事情...但如果这些都没有，那么我想要它 .push（）

If I tried to push again into the array with either name: "tom" or text: "tasty", I don't want anything to happen... but if neither of those are there then I want it to .push()

我该怎么做？

推荐答案

您可以使用自定义方法扩展Array原型：

You could extend the Array prototype with a custom method:

// check if an element exists in array using a comparer function
// comparer : function(currentElement)
Array.prototype.inArray = function(comparer) { 
    for(var i=0; i < this.length; i++) { 
        if(comparer(this[i])) return true; 
    }
    return false; 
}; 

// adds an element to the array if it does not already exist using a comparer 
// function
Array.prototype.pushIfNotExist = function(element, comparer) { 
    if (!this.inArray(comparer)) {
        this.push(element);
    }
}; 

var array = [{ name: "tom", text: "tasty" }];
var element = { name: "tom", text: "tasty" };
array.pushIfNotExist(element, function(e) { 
    return e.name === element.name && e.text === element.text; 
});

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