Array.sort（）不能正确排序数字 [英] Array.sort() doesn't sort numbers correctly
问题描述
在Chrome 14和Firefox 5（尚未测试其他浏览器）中，以下代码未对数字进行正确排序：
In Chrome 14, and Firefox 5 (haven't tested other browsers), the following code doesn't sort the numbers correctly:
<script>
a = new Array();
a.push(10);
a.push(60);
a.push(20);
a.push(30);
a.push(100);
document.write(a.sort())
</script>
它返回10,100,20,30,60
It returns 10,100,20,30,60
我尝试了不同的数字，它总是表现为0不存在，否则正确排序数字。有谁知道为什么？
I've tried different numbers, and it always acts as if the 0s aren't there and sorts the numbers correctly otherwise. Anyone know why?
推荐答案
我尝试过不同的数字，它总是表现得好像0不存在，否则正确排序数字。有谁知道为什么？
I've tried different numbers, and it always acts as if the 0s aren't there and sorts the numbers correctly otherwise. Anyone know why?
你得到一个词典排序（例如将对象转换为字符串，并按字典顺序对它们进行排序），是Javascript中的默认排序行为：
You're getting a lexicographical sort (e.g. convert objects to strings, and sort them in dictionary order), which is the default sort behavior in Javascript:
https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/sort
array.sort([compareFunction])
参数
compareFunction
compareFunction
指定定义排序顺序的函数。如果省略，则根据每个元素的字符串转换按字典顺序（按字典顺序）对数组进行排序。
Specifies a function that defines the sort order. If omitted, the array is sorted lexicographically (in dictionary order) according to the string conversion of each element.
在ECMAscript规范中（通用Javascript的规范性参考， ECMA-262，3rd ed 。，第15.4.4.11节，默认排序顺序是字典顺序，虽然它们没有出来并说出来，而是给出了一个概念排序函数的步骤，如果需要的话调用给定的比较函数，否则比较转换为字符串时的参数：
In the ECMAscript specification (the normative reference for the generic Javascript), ECMA-262, 3rd ed., section 15.4.4.11, the default sort order is lexicographical, although they don't come out and say it, instead giving the steps for a conceptual sort function that calls the given compare function if necessary, otherwise comparing the arguments when converted to strings:
13. If the argument comparefn is undefined, go to step 16.
14. Call comparefn with arguments x and y.
15. Return Result(14).
16. Call ToString(x).
17. Call ToString(y).
18. If Result(16) < Result(17), return −1.
19. If Result(16) > Result(17), return 1.
20. Return +0.
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