如何获取所有已打开的子窗口的引用 [英] How to get the references of all already opened child windows

问题描述

我想获取所有已打开的子窗口的引用。有什么办法吗？我没有使用 child = window.open（....）只使用 window.open（....）并打开多个子窗口。

I want to get the references of all already opened child windows. is there any way? I am not using child = window.open(....) just using window.open(....) and opening multiple child windows.

推荐答案

如果您不想更改当前代码，可以直接覆盖 window.open（） function：

If you don't want to change your current code, you can simply override window.open() function:

var openedWindows = [];
window._open = window.open; // saving original function
window.open = function(url,name,params){
    openedWindows.push(window._open(url,name,params));
    // you can store names also...
}

运行这个调用 window.open（）之前的代码。对打开的窗口的所有引用都将存储在 openedWindows 数组中。您可以在任何地方访问它们

Run this code before calling window.open(). All the references to the opened windows will be stored in openedWindows array. You can access them anywhere you want

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