socket.io删除特定的侦听器 [英] socket.io Removing specific listener

问题描述

我正在使用Socket.io v0.9.16和
Chrome 34

I'm using Socket.io v0.9.16 and Chrome 34

我正在尝试删除特定的侦听器，或者取消订阅某个特定的侦听器订阅

I'm trying to remove a specific listener, or unsubscribe from a specific subscription

这样的事情：

socket.on('testComplete',function(data){
    console.log('test complete',data);
}); 

function emitTest(){
    console.log('emitting test');
    socket.emit('test','first emit');
}

function removeListener(){
    socket.removeListener('testComplete');
}

如果我拨打 emitTest function，然后是 removeListener 函数，当我调用<$时，我仍然看到'test complete'消息再次c $ c> emitTest 。如果套接字函数工作，则应该删除监听器。

If I call the emitTest function, and then the removeListener function, I still see the 'test complete' message when I call emitTest again. The listener should have been removed, if the socket function even works.

我正在寻找一种方法来删除实际的特定的监听器工作。

I'm looking for a way to remove a specific listener that actually works.

这个答案说removeListener不起作用。

This answer says that removeListener doesn't work.

这样做是否有任何缺点：

Is there any downside to just doing this:

socket.removeListener=function(name){
        if(socket.$events.hasOwnProperty(name)){
            delete socket.$events[name];
        }
    };

我将答案标记为正确，但我在我的代码中使用了上述内容，因为它更好用我的设计。

I marked an answer as correct, but I'm using the above in my code since it works better with my design.

推荐答案

你需要将监听器功能传递给 removeListener 。

You need to pass in the listener function to removeListener.

function testFun(data){
    console.log('test complete',data);
}

socket.on('testComplete', testFun); 

function emitTest(){
    console.log('emitting test');
    socket.emit('test','first emit');
}

function removeListener(){
    socket.removeListener('testComplete', testFun);
}

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