$ getJSON和for循环问题 [英] $getJSON and for loop issue
问题描述
这是用表格填充从MediaWiki API查询返回的结果数量 /api.php?action=query&list=querypage&qppage=BrokenRedirects
。然后将结果数添加到id中,例如:
This is to populate a table with the amount of results that are returned from the MediaWiki API query /api.php?action=query&list=querypage&qppage=BrokenRedirects
. The number of results is then added to the id, for example:
// BrokenRedirects
$.getJSON('/api.php?action=query&list=querypage&qppage=BrokenRedirects&format=json', function (data) {
$('#BrokenRedirects').text(data.query.querypage.results.length);
});
但是,由于它重复了7次,我将qppage的参数变成了一个数组并使用了一个循环缩短整体代码。
But as it's being repeated another 7 times I made the arguments for qppage into an array and used a for loop to shorten overall code.
var array = ['BrokenRedirects',
'DoubleRedirects',
'Unusedcategories',
'Unusedimages',
'Wantedcategories',
'Wantedfiles',
'Wantedpages',
'Wantedtemplates'];
for (var i = 0; i < array.length; i++) {
$.getJSON('/api.php?action=query&list=querypage&qppage=' + array[i] + '&format=json', function (data) {
$('#' + array[i]).text(data.query.querypage.results.length);
});
}
第一个未开环的版本有效。但是当我添加一个循环时它没有。 $ getJSON
部分执行,但它无法将结果数据添加到id。我通过JSLint运行它,除了抱怨循环中的函数,并声明 var i
与 var array
返回一点帮助。我对javascript相对缺乏经验,所以想到一个变量不能在循环中使用两次?除此之外,可能与在循环中使用id有关吗?
The first, unlooped, version works. But when I added a loop it didn't. The $getJSON
part executes, but it then fails to add the resultant data to the id. I ran it through JSLint which apart from complaining about functions in a loop and declaring var i
with var array
returned little help. I'm relatively inexperienced with javascript so thought perhaps a variable can't be used twice within a loop? Other than that, maybe something to do with using an id within a loop?
推荐答案
这是一个经典问题: i
在调用回调时具有循环结束的值。
That's a classical problem : i
has the value of end of loop when the callback is called.
你可以像这样解决它:
for (var i = 0; i < array.length; i++) {
(function(i) { // protects i in an immediately called function
$.getJSON('/api.php?action=query&list=querypage&qppage=' + array[i] + '&format=json', function (data) {
$('#' + array[i]).text(data.query.querypage.results.length);
});
})(i);
}
2018年附录:
在今天的浏览器中现在有另一个更清洁的解决方案:使用让
代替 var
:
There's now another cleaner solution in today's browsers: use let
instead of var
:
for (let i = 0; i < array.length; i++) {
$.getJSON('/api.php?action=query&list=querypage&qppage=' + array[i] + '&format=json', function (data) {
$('#' + array[i]).text(data.query.querypage.results.length);
});
}
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