正则表达式在方括号之间抓取字符串 [英] Regex to grab strings between square brackets

问题描述

我有以下字符串： pass [1] [2011-08-21] [total_passes]

如何将方括号之间的项目提取到数组中？我试过

How would I extract the items between the square brackets into an array? I tried

匹配（/ \ [（。*？）\] /）;

var s = 'pass[1][2011-08-21][total_passes]';
var result = s.match(/\[(.*?)\]/);

console.log(result);

但这只返回 [1] 。

不知道如何做到这一点..提前谢谢。

Not sure how to do this.. Thanks in advance.

推荐答案

你几乎就在那里，你只需要一个全球匹配（请注意 / g flag）：

You are almost there, you just need a global match (note the /g flag):

match(/\[(.*?)\]/g);

示例： http://jsfiddle.net/kobi/Rbdj4/

如果你想要的东西只捕获组（来自 MDN ）：

If you want something that only captures the group (from MDN):

var s = "pass[1][2011-08-21][total_passes]";
var matches = [];

var pattern = /\[(.*?)\]/g;
var match;
while ((match = pattern.exec(s)) != null)
{
  matches.push(match[1]);
}

示例： http://jsfiddle.net/kobi/6a7XN/

另一种选择（我通常更喜欢），滥用替换回调：

Another option (which I usually prefer), is abusing the replace callback:

var matches = [];
s.replace(/\[(.*?)\]/g, function(g0,g1){matches.push(g1);})

示例： http：// jsfiddle。 net / kobi / 6CEzP /

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