有效地对word_number键上的字典（或js中的任何键值数据结构）进行排序 [英] sort a dictionary (or whatever key-value data structure in js) on word_number keys efficiently

问题描述

如何按键对词典进行排序，如

how do I sort a dictionary by key like

dict["word_21"] = "Hello Java";
dict["word_22"] = "Hello World";
dict["word_11"] = "Hello Javascript";

因此我得到

dict["word_22"] = "Hello World";
dict["word_21"] = "Hello Java";
dict["word_11"] = "Hello Javascript";

索引上只有word_number组合，值是字符串。索引是不同的（没有相等的值）但在错误情况下可能是未定义的

There are word_number combinations on indices only and the values are strings. The indices are distinct (no equal values) but could be "undefined" in an error case

编辑：实际上我需要它的降序和升序。但降序是目前我需要的。

Actually I need the descending and ascending order of it. But the descending order is what I need at the moment.

推荐答案

试试这个

var sorted = [];
for(var key in dict) {
    sorted[sorted.length] = key;
}
sorted.sort();

在其键上排序 dict 并编写回到对象对我来说没有意义，但在这里：

Sorting dict on its keys and writing it back to the object does not make sense to me, but here it goes:

function sortOnKeys(dict) {

    var sorted = [];
    for(var key in dict) {
        sorted[sorted.length] = key;
    }
    sorted.sort();

    var tempDict = {};
    for(var i = 0; i < sorted.length; i++) {
        tempDict[sorted[i]] = dict[sorted[i]];
    }

    return tempDict;
}

dict = sortOnKeys(dict);

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