jQuery获得子div的最大宽度 [英] jQuery get max width of child div's
问题描述
我需要在包装器div元素中获取子div的最大宽度(仅一个宽度)
I need to get the max width(just the one width) of the child div in the wrapper div element
<div id="wrapper">
<div class="image"><img src="images/1.jpg"></div>
<div class="image"><img src="images/2.jpg"></div>
<div class="image"><img src="images/3.jpg"></div>
<div class="image"><img src="images/4.jpg"></div>
<div class="image"><img src="images/5.jpg"></div>
<div class="image"><img src="images/6.jpg"></div>
</div>
推荐答案
Math.max.apply(Math, $('.image').map(function(){ return $(this).width(); }).get());
根据建议,我会将其分解:
Per suggestion, I'll break that down:
$('.image').map(function(){
return $(this).width();
}).get();
以上获取所有 .image
divs并将其转换为宽度列表。所以你现在有类似的东西: [200,300,250,100,400]
。正如Felix指出的那样, .get()
是获取实际数组而不是jQuery数组所必需的。
The above gets a list of all .image
divs and converts it into a list of their widths. So you'll now have something like: [200, 300, 250, 100, 400]
. The .get()
, as Felix pointed out, is necessary to get an actual Array instead of a jQuery array.
Math.max
接受N个参数,因此您必须将其称为: Math.max(200,300,250,100,400)
,这是 Math.max.apply
作品完成的内容。
Math.max
takes N arguments, so you have to call it as: Math.max(200, 300, 250, 100, 400)
, which is what the Math.max.apply
piece accomplishes.
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