Math.min.apply（0，array） - 为什么？ [英] Math.min.apply(0, array) - why?

问题描述

我只是在挖掘一些JavaScript代码（Raphaël.js）并遇到以下行（稍微翻译）：

I was just digging through some JavaScript code (Raphaël.js) and came across the following line (translated slightly):

Math.min.apply(0, x)

其中 x 是一个数组。为什么你会这样做？行为似乎是从数组中获取最小值 x 。

where x is an array. Why on earth would you do this? The behavior seems to be "take the min from the array x."

推荐答案

当我发布自己的问题时，我意识到了答案：这个 是获取数组 x 的最简洁方法JavaScript的。第一个论点是完全随意的;我发现0令人困惑，因为代码直观地意味着取0和x的最小值，这绝对不是这种情况。使用Math对象对于人类可读性更有意义，但Raphael.js作者痴迷于缩小，0缩短了三个字节。

I realized the answer as I was posting my own question: This is the most succinct way of taking the min of an array x in JavaScript. The first argument is totally arbitrary; I find the 0 confusing because the code intuitively means "Take the min of 0 and x," which is absolutely not the case. Using the Math object makes more sense for human-readability, but the Raphael.js authors are obsessed with minification and 0 is three bytes shorter.

参见 http://ejohn.org/blog/fast-javascript-maxmin/

为了便于阅读，我强烈建议人们停止这样做，而是按照

For readability's sake, I'd strongly urge people to stop doing this and instead define a function along the lines of

function arrayMin(arr) { return Math.min.apply(Math, arr); };

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