如何将数组数组中相同索引处的元素加到一个数组中? [英] How to sum elements at the same index in array of arrays into a single array?

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问题描述

假设我有一个数组数组,如下所示:

Let's say that I have an array of arrays, like so:

[
  [0, 1, 3],
  [2, 4, 6],
  [5, 5, 7],
  [10, 0, 3]
]

如何生成一个新数组,该数组在javascript中对内部数组的每个位置的所有值求和?在这种情况下,结果将是:[17,19,19]。无论内部数组的长度如何,我都需要能够提供一个有效的解决方案。我认为这可以使用map和for-of的一些组合,或者可能减少,但我不能完全围绕它。我已经搜索但找不到任何与此匹配的例子。

How do I generate a new array that sums all of the values at each position of the inner arrays in javascript? In this case, the result would be: [17, 10, 19]. I need to be able to have a solution that works regardless of the length of the inner arrays. I think that this is possible using some combination of map and for-of, or possibly reduce, but I can't quite wrap my head around it. I've searched but can't find any examples that quite match this one.

推荐答案

你可以使用 Array.prototype.reduce() Array.prototype.forEach()

You can use Array.prototype.reduce() in combination with Array.prototype.forEach().

var array = [
        [0, 1, 3],
        [2, 4, 6],
        [5, 5, 7],
        [10, 0, 3]
    ],
    result = array.reduce(function (r, a) {
        a.forEach(function (b, i) {
            r[i] = (r[i] || 0) + b;
        });
        return r;
    }, []);
document.write('<pre>' + JSON.stringify(result, 0, 4) + '</pre>');

更新,通过采用减少数组的地图来缩短方法。

Update, a shorter approach by taking a map for reducing the array.

var array = [[0, 1, 3], [2, 4, 6], [5, 5, 7], [10, 0, 3]],
    result = array.reduce((r, a) => a.map((b, i) => (r[i] || 0) + b), []);
    
console.log(result);

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