window.open()在第二次调用时返回undefined或null [英] window.open() returns undefined or null on 2nd call

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本文介绍了window.open()在第二次调用时返回undefined或null的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下情况:

我点击一个链接:
打开一个名为'popup'的弹出窗口,在其中加载一个pdf(在IE6)。

I click a link which: opens a popup window called 'popup' which loads a pdf inside of it (in IE6).

没有关闭弹出窗口,我再次点击链接,这应该重新打开弹出窗口中的pdf,而是抛出javascript错误:
未找到成员

without closing the popup, i click the link again, which should reopen the pdf inside the popup, but instead a javascript error in thrown: member not found

用于打开弹出窗口的javascript函数是:

the javascript function used to open the popup is:

function openWindow(url, name, props) {
  var windowRef = window.open(url, name, props);
  if (!windowRef.opener) {
    windowRef.opener = self;
  }
  windowRef.focus(); //error at this line, windowRef must be null
  return windowRef;
}

问题:
如何解决这个问题,而不打开每次都有新的弹出窗口?

question: how do i get around this, without opening a new popup window every time?

推荐答案

这是互联网上每个人都在使用的黑客行为:

this is the hack that works that everyone on the internets is using:

function openWindow(url, name, props) {
  if(/*@cc_on!@*/false){ //do this only in IE
    var windowRef = window.open("", name, props);
    windowRef.close();
  }
  var windowRef = window.open(url, name, props);
  if (!windowRef.opener) {
    windowRef.opener = self;
  }
  windowRef.focus();
  return windowRef;
}

这篇关于window.open()在第二次调用时返回undefined或null的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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