如何比较两个对象数组并获取常见对象 [英] How to compare two array of object and get common objects

问题描述

大家好我有两个数组

var elements = [{
        "id": "id_1",
        "type": "input",
        "businesstype": { "type": "text" }
    },
    {
        "type": "label",
        "id": "id_234"
    },
    {
        "id": "id_16677",
        "type": "div",
    },
    {
        "id": "id_155",
        "type": "input",
        "businesstype": { "type": "password" }
    }
]

var filterArray=[{type:'input',businesstype:{type:'text'}},{type:'div'}]

并想要像

var output = [{
        "id": "id_1",
        "type": "input",
        "businesstype": { "type": "text" }
    },
    {
        "id": "id_16677",
        "type": "div",
    }
]

如何比较这两个对象以获得来自el的相等对象ements。

How do I compare these two objects to get equal objects from elements.

推荐答案

您可以使用嵌套对象的递归方法对其进行过滤。

You could filter it with a recursive approach for the nested objects.

const isObject = o => o && typeof o === 'object',
      isEqual = (f, o) =>
          isObject(o) && Object.keys(f).every(k =>
              isObject(f[k]) && isEqual(f[k], o[k]) || o[k] === f[k]
          );

var elements = [{ id: "id_1", type: "input", businesstype: { type: "text" } }, { type: "label", id: "id_234" }, { id: "id_16677", type: "div" }, { id: "id_155", type: "input", businesstype: { type: "password" } }],
    filterArray = [{ type: 'input', businesstype: { type: 'text' } }, { type: 'div' }],
    result = elements.filter(o => filterArray.some(f => isEqual(f, o)));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

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