从1到100，打印“ping”如果是3，“pong”的倍数。如果是5的倍数，或者打印数字 [英] From 1 to 100, print "ping" if multiple of 3, "pong" if multiple of 5, or else print the number

问题描述

我刚从求职面试回家，面试官要我写一个程序：

I just came home from a job interview, and the interviewer asked me to write a program:

它应该从1到100计算，并打印.. 。

It should, count from 1 to 100, and print...

如果它是3的倍数，ping


如果它是5的倍数，pong

否则，打印数字。

If it was multiple of 3, "ping"
If it was multiple of 5, "pong"
Else, print the number.

如果它是3和5的倍数（如15），则应打印ping和pong。

If it was multiple of 3 AND 5 (like 15), it should print "ping" and "pong".

我选择了Javascript，并想出了这个：

I chose Javascript, and came up with this:

for (x=1; x <= 100; x++){
    if( x % 3 == 0 ){
        write("ping")
    }
    if( x % 5 == 0 ){
        write("pong")
    }
    if( ( x % 3 != 0 ) && ( x % 5 != 0 ) ){
        write(x)
    }
}

Actualy，我对我非常不满意解决方案，但我无法找到更好的解决方案。

Actualy, I left very unhappy with my solution, but I can't figure out a better one.

有谁知道更好的方法吗？
这是两次检查，我不喜欢它。
我在家里进行了一些测试，没有成功，这是唯一一个返回正确答案的测试...

Does anyone knows a better way to do that? It's checking twice, I didn't like it. I ran some tests here at home, without success, this is the only one that returns the correct answer...

推荐答案

你的解决方案非常令人满意恕我直言。很难，因为半数不是3或5的倍数，我会从另一个方向开始：

Your solution is quite satisfactory IMHO. Tough, as half numbers are not multiple of 3 nor 5, I'd start the other way around:

for (var x=1; x <= 100; x++){
    if( x % 3 && x % 5 ) {
        document.write(x);
    } else {
        if( x % 3 == 0 ) {
            document.write("ping");
        }
        if( x % 5 == 0 ) {
            document.write("pong");
        }
    }
    document.write('<br>'); //line breaks to enhance output readability
}​

小提琴

此外，请注意<$ c以外的任何数字$ c> 0 和 NaN 是真值，所以我删除了不必要的！= 0 和一些括号。

Also, note that any number other than 0 and NaN are truthy values, so I've removed the unnecessary != 0 and some pairs of parenthesis.

这是另一个版本，它不会使模数运算两次但是需要存储变量：

Here's another version, it doesn't make the same modulus operation twice but needs to store a variable:

for (var x=1; x <= 100; x++) {
    var skip = 0;
    if (x % 3 == 0) {
        document.write('ping');
        skip = 1;
    }
    if (x % 5 == 0) {
        document.write('pong');
        skip = 1;
    }
    if (!skip) {
        document.write(x);
    }
    document.write('<br>'); //line breaks to enhance output readability
}

小提琴

这篇关于从1到100，打印“ping”如果是3，“pong”的倍数。如果是5的倍数，或者打印数字的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！