提交后成功/失败消息弹出框？ [英] successful/fail message pop up box after submit?
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问题描述
基本上单击提交按钮后，我想弹出一个弹出框说成功或失败，然后单击确定以确认消息。目前我得到一个弹出框未定义，然后是失败的消息弹出框。 请帮忙！
Basically after clicking the submit button, I want a pop up box to pop up saying successful or fail, then clicking OK to confirm the message. At the moment i am getting a pop up box "undefined" followed by failed message pop up box. HELP PLEASE!
这里是脚本
<?php
include ('config.php');
if (isset($_POST['name'])) {
$name = "name";
$query = "INSERT INTO pop ('id','name') VALUES ('','$name')";
$result = mysql_query($query,$cn);
if ($result) {
echo "<script type='text/javascript'>alert('submitted successfully!')</script>";
}
else
{
echo "<script type='text/javascript'>alert('failed!')</script>";
}
}
?>
<html>
<head>
</head>
<body>
<form action="" method="post">
Name:<input type="text" id="name" name="name"/>
<input type="submit" value="submit" name="submit" onclick="alert();"/>
</form>
</body>
推荐答案
您正在回显HTML的body标签之外。
把你的回声放在那里，你应该没事。
You are echoing outside the body tag of your HTML. Put your echos there, and you should be fine.
另外，删除 onclick =alert（）来自您的提交。这是您的第一个未定义消息的原因。
Also, remove the onclick="alert()" from your submit. This is the cause for your first undefined message.
<?php
$posted = false;
if( $_POST ) {
$posted = true;
// Database stuff here...
// $result = mysql_query( ... )
$result = $_POST['name'] == "danny"; // Dummy result
}
?>
<html>
<head></head>
<body>
<?php
if( $posted ) {
if( $result )
echo "<script type='text/javascript'>alert('submitted successfully!')</script>";
else
echo "<script type='text/javascript'>alert('failed!')</script>";
}
?>
<form action="" method="post">
Name:<input type="text" id="name" name="name"/>
<input type="submit" value="submit" name="submit"/>
</form>
</body>
</html>
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