在json中发送编码响应 [英] Sending encoding response in json

问题描述

我正在使用的项目中使用了很多jQuery。

I am using a lot of jQuery in a project am working on.

我有一个javascript函数，它向一个以JSON方式返回数据的控制器发出ajax请求。

I have a javascript function that makes an ajax request to a controller which returns data in JSON.

我想显示一条用户友好的消息，通知用户他/她尚未存储任何信息。但是我对如何在JSON中发送响应感到困惑，所以我的javascript函数可以确定用户是否有要显示的信息。

I would like to display a user friendly message informing the user that he/she has no information stored yet. But I'm confused as to how to send a response in JSON so my javascript function can determine whether the user has information to be displayed.

这是我的javascript函数：

Here is my javascript function:

function latest_pheeds() {
    var action = url+"pheeds/latest_pheeds";
    $('#pheed-stream').html('<div class="loading"></div>');
    $('.loading').append('<img src="'+pheed_loader_src+'" />');
    $.ajax({
        url:action,
        type:'GET',
        dataType:'json',
        error: function () {
        },
        success:function(data) {
            $('.loading').fadeOut('slow');
            $.each(data,function(index,item) {
            $('#pheed-stream').append
            (
            '<div class="pheed" id="'+item.pheed_id+'">'+
            '<p><a class="user_trigger" href="users/info/'+item.user_id+'">'
            +item.user_id+'</a></p>'+
            '<p>'+item.pheed+'</p>'+
            '<div class="pheed_meta">'+
            '<span>'+item.datetime+' Ago</span>'+
            '<span class="cm">'+item.comments+
            '<img class="comment_trigger" src="/pheedbak/assets/img/comment.png" title="Click to comment on pheed" onclick="retrieve_comments('+item.pheed_id+')">'+
            '</span>'+
            '<span>'+item.repheeds+
            ' Repheeds'+
            '<img class="repheed_trigger" src="/pheedbak/assets/img/communication.png" title="Click to repheed" onclick="repheed('+item.pheed_id+')">'+
            '</span>'+
            '<span>'+
            'Favourite'+
            '<img class="favourite_trigger" src="/pheedbak/assets/img/star.png" title="Click to make this a favourite" onclick="favourite_pheed('+item.pheed_id+')" />'+
            '</span>'+
            '</div>'+
            '</div>'
            );
        });
        }
    });
}

继承人ajax请求的控制器功能

And heres the controller function the ajax request is made to

function latest_pheeds() {
    //Confirm if a user is logged before allowing access
    if($this->isLogged() == true) {
        //load the pheed model for database interaction
        $this->load->model('pheed_model');
        //load user model
        $this->load->model('user_model');
        //load comment model
        $this->load->model('comment_model');
        //store the pheeds to a the $data variable
        $data = $this->pheed_model->get_latest_pheeds();
        //Load the date helper to calculate time difference between post time and current time
        $this->load->helper('date');
        //Current time(unix timetamp)
        $time = time();
        //pheeds
        $pheeds = array();
        if(count($data) > 0 ) {
            foreach($data as $pheed) {
                $row['pheed_id'] = $pheed->pheed_id;
                $row['user_id'] = $this->user_model->return_username($pheed->user_id);
                $row['pheed'] = $pheed->pheed;
                $row['datetime'] = timespan($pheed->datetime,$time);
                $row['comments'] = $this->comment_model->count_comments($pheed->pheed_id);
                $row['repheeds'] = $pheed->repheeds;
                $pheeds[] = $row;
            }

            echo json_encode($pheeds);
            $response['response'] = "Ok";
            $res[] = $response;
            echo json_encode($res)."\n";
        }
    } else {

    }

它生成JSON输出，但语法被破坏所以我无法用javascript，
读取它但是一旦我从上面的方法中删除了以下代码它正常工作

It generates the JSON output,but the syntax is broken so i cant read it with javascript, but once i get rid of the following code from the above method it works normally

  $response['response'] = "Ok";
  $res[] = $response;
  echo json_encode($res)."\n";

推荐答案

你必须只使用一次json_encode（$ data）一个响应，如果你想输出更多的东西，你需要将你的数据合并到一个数组并发送它。

You MUST only use json_encode($data) once in a response, if you want to output more stuff, you need to merge your data into one array and send that.

编辑：要清楚，你可以做一种方法它是这样的：

To be clear, one way you could do it is like this:

echo json_encode(array('pheeds' => $pheeds, 'res' => $res));

然后在JS中你会得到一个带有pheeds和res键的数组。

Then in JS you will get an array with the keys "pheeds" and "res".

虽然它可能没什么实际意义，但我建议你在回显json编码的字符串之前这样做：

Although it may be of little practical significance, I would also recommend doing this before you echo the json encoded string:

header('Content-Type: application/json');

这篇关于在json中发送编码响应的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！