正则表达式替换在引号之间输入 [英] Regex replace enters between quotes
问题描述
如何替换文本文件中两个引号之间的所有输入。第一个引号始终以制表符开头,或者它是行中的第一个字符(csv文件)。我尝试了下面的正则表达式
How do i replace all enters between two quotes in a text file. The first quote is always preceded by a tab or it is the first character in the row (csv file). I tried the following regex
/(\t"|^")([^"]*)(\n)([^"]*")/gm
但这个正则表达式只匹配两个之间的第一个输入报价,不是全部。
but this regex only matches the first enter between two quotes, not all.
例如,以下文字:
xx "xx
xx
xx"
xx
"xx"
xx
xx
"xxx xxx
xx"
应该成为
xx "xx xx xx"
xx
"xx"
xx
xx
"xxx xxx xx"
我阅读了以下帖子(
javascript正则表达式替换括号之间的空格)这非常相似,但正则表达式建议在我的情况下不可用。
I read the following post ( javascript regex replace spaces between brackets ) which is very similar, but the regex suggested there is not useable in my situation.
推荐答案
使用Javascript替换你可以使用函数作为替换。
With Javascript replace you can use a function as replacement.
var str = 'foo \n"a\n" bar\n';
str = str.replace(/"[^"]+"/g, function(m) {
return m.replace(/\n/g, ' ');
});
console.log(str);
正则表达式 [^] +
将引用的内容与一个或多个非引用相匹配。
The regex "[^"]+"
will match quoted stuff with one or more non-quotes in between.
根据需要添加选项卡或开始条件等条件: (?:\t | ^)[^] +
Add conditions such as tab or start to the pattern as needed: (?:\t|^)"[^"]+"
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