jqGrid格式化程序和可排序列 - 不排序 [英] jqGrid formatter and sortable column - doesn't sort
问题描述
我正在为我的jqGrid columnModel使用自定义格式化程序,我无法使用格式化程序函数进行排序。如果我删除formatter列正常排序。
I am using a custom formatter for my jqGrid columnModel and I can't get sorting to work with formatter functions. If I remove formatter column sorts normally.
jQuery("#listAgentOptions").jqGrid({
height: 240,
datatype: "local",
colNames: [' ', 'First Name', 'Last Name', 'Role'],
colModel: [
{ name: 'status', index: 'status', width: 18, sorttype: 'text', align: 'center', formatter: function(cellvalue, options, rowObject) {
return cellvalue == 1 ? "<img src='images/agent_green_s.png' alt='Ready' title='Ready' />" :
cellvalue == 3 ? "<img src='images/agent_red_s.png' alt='Busy' title='Busy' />" :
"<img src='images/agent_orange_s.png' alt='Pending Ready' title='Pending Ready' />";
},
unformat:
function(cellvalue, options, rowObject) { return Math.floor(Math.random() + 0.1).toString(); }
},
{ name: 'firstName', index: 'firstName', width: 92 },
{ name: 'lastName', index: 'lastName', width: 142 },
{ name: 'role', index: 'role', sorttype: 'int', width: 36, align: 'center', formatter: function(cellvalue, options, rowObject) {
return cellvalue == true ? "<img src='images/user_gray.png' alt='Supervisor' title='Supervisor' />" : "<img src='images/user.png' alt='Agent' title='Agent' />";
}, unformat:
function(cellvalue, options, rowObject) { return cellvalue; }
}
],
sortname: 'lastName'
});
行添加如下:
jQuery("#listAgentOptions").jqGrid('clearGridData');
$.each(result, function(i, item) {
if (item.ContactType == 1) {
jQuery("#listAgentOptions").jqGrid('addRowData', i+1, { firstName: item.ContactName.split(" ")[0], lastName: item.ContactName.split(" ")[1],
role: item.IsSupervisor,
status: item.Status == "Ready" ? 1 : item.Status == "Busy" ? 3 : 2
});
}
});
如何让排序正常工作?
更新。我刚刚下载了最新版本的jqGrid - 同样的问题。
Update. I have just downloaded the latest version of jqGrid - same issue.
我也试过使用 unformat:function(cellvalue,options,rowObject){}
但是cellvalue在那里是空的:-E当我使用时返回Math.floor(Math.random()+ 0.1) .toString();
它会随机排序(每次单击),但返回cellvalue;
只返回一个空字符串。
I have also tried using unformat: function(cellvalue, options, rowObject) { }
but cellvalue is empty there :-E When I use return Math.floor(Math.random() + 0.1).toString();
it does sort things randomly (each time I click), but return cellvalue;
just returns an empty string.
推荐答案
好的,我已经知道发生了什么。
OK, I have figured out what's going on.
首先你必须使用 unformat
将初始值传递回jqGrid排序函数。
First of all you have to use unformat
to pass the initial value back to jqGrid sort function.
jqGrid传递 $(row).text()
到 unformat
函数,对于只有html标记的单元格返回一个空字符串,然后无法改变它。但是,你可以做的是使用 unformat
函数的第三个参数,在我的例子中是 rowObject
。然后,您可以使用 $(rowObject).html()
检索实际单元格值,并将其解析回值。排序现在可以正常工作。
jqGrid is passing $(row).text()
to unformat
function, which for cells with just an html tag returns an empty string, and there is no option to change it. However, what you can do is use the third parameter of unformat
function, which in my case is rowObject
. You can then retrieve the actual cell value by using $(rowObject).html()
and parse it back to the value. Sorting will now work.
另外要记住的是,如果你使用的是 sorrtype:'int'
你会必须将整数作为字符串返回,例如 return'1';
。
Another thing to remember is that if you are using sorrtype: 'int'
you will have to return integer as a string, like return '1';
.
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