查询联系人的所有电话号码（解决） [英] Querying all phone numbers of a contact (SOLVED)
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问题描述
我设法编写补充程序，当用户点击一个按钮，他将能够检索一个电话号码，将填补一个EditText框。的问题是，如果一个接触有多个号码，它将始终以最顶部的数目
我一直在读另一个线程，从联系人获取号码选取器，有一个答案，但我不明白这一点。由于我是新来的Android程序， 我将AP preciate如果有任何人可以给我一步一步的说明
更新
在尝试，我发现这工作。唯一的问题是，我如何与电话号码显示的电话类型
公共类测试扩展活动{
/ **第一次创建活动时调用。 * /
私有静态最终诠释CONTACT_PICKER_RESULT = 1001;
@覆盖
公共无效的onCreate（包savedInstanceState）{
super.onCreate（savedInstanceState）;
的setContentView（R.layout.main）;
按钮浏览=（按钮）findViewById（R.id.do_email_picker）;
browse.setOnClickListener（新View.OnClickListener（）{
公共无效的onClick（视图v）{
// TODO自动生成方法存根
意图contactPickerIntent =新的意图（Intent.ACTION_PICK，Contacts.CONTENT_URI）;
startActivityForResult（contactPickerIntent，CONTACT_PICKER_RESULT）;
}
}）;
}
@覆盖
保护无效onActivityResult（INT申请code，INT结果code，意图数据）{
// TODO自动生成方法存根
super.onActivityResult（要求code，因此code，数据）;
如果（结果code == RESULT_OK）{
开关（要求code）{
案例CONTACT_PICKER_RESULT：
//把手接触结果
最后的EditText smsEntry =（EditText上）findViewById（R.id.sms_to）;
光标光标= NULL;
字符串PHONENO =;
名单＆LT;字符串＆GT; allNumbers =新的ArrayList＆LT;字符串＆GT;（）;
INT phoneIdx = 0;
尝试{
开放的结果= data.getData（）;
Log.v（Akiff，有一个接触的结果：+ result.toString（））;
//从URI获得接触式ID
字符串ID = result.getLastPathSegment（）;
//查询一切手机
光标= getContentResolver（）查询（Phone.CONTENT_URI，空，Phone.CONTACT_ID +=？，新的String [] {ID}，空）。
phoneIdx = cursor.getColumnIndex（Phone.DATA）;
//就让我们每个电话号码
如果（cursor.moveToFirst（））{
而（cursor.isAfterLast（）== FALSE）{
PHONENO = cursor.getString（phoneIdx）;
allNumbers.add（PHONENO）;
cursor.moveToNext（）;
}
}其他{
Log.w（AKIFF，无号）;
Toast.makeText（Test.this，这种接触没有号码，Toast.LENGTH_LONG）.show（）;
}
}赶上（例外五）{
Log.e（AKIFF，错误，E）;
}最后{
如果（光标！= NULL）{
cursor.close（）;
}
最终的String []项目= allNumbers.toArray（新的String [allNumbers.size（））;
AlertDialog.Builder建设者=新AlertDialog.Builder（Test.this）;
builder.setTitle（选择一个数字：）;
builder.setItems（项目，新DialogInterface.OnClickListener（）{
公共无效的onClick（DialogInterface对话，诠释项）{
// TODO自动生成方法存根
字符串selectedNumber =项目[项目]的ToString（）;
selectedNumber = selectedNumber.replace（ - ，）;
// selectedNumber = selectedNumber.replace（+，）;
smsEntry.setText（selectedNumber）;
}
}）;
AlertDialog警报= builder.create（）;
如果（allNumbers.size（）→1）{
alert.show（）;
}其他{
串selectedNumber = phoneNo.toString（）;
selectedNumber = selectedNumber.replace（ - ，）;
smsEntry.setText（selectedNumber）;
}
如果（phoneNo.length（）== 0）{
Log.d（Akiff，不接触）;
}
}
打破;
}
}其他{
//优雅地处理故障
Log.w（Akiff，警告行为不好吗？）;
}
}
解决方案
首先，你可能需要查询在电话簿中的所有联系人。
//运行查询
开放的我们的uri = ContactsContract.Contacts.CONTENT_URI;
的String []投影=新的String [] {
ContactsContract.Contacts._ID，
ContactsContract.Contacts.DISPLAY_NAME
};
串选择= ContactsContract.Contacts.IN_VISIBLE_GROUP +='1';
的String [] selectionArgs两个= NULL;
字符串排序顺序= ContactsContract.Contacts.DISPLAY_NAME +分页中局部ASC;
//构建适配器的联系人条目
光标mCursor = managedQuery（URI，投影，选择，selectionArgs两个，排序顺序）;
//
//绑定mCursor到你的列表视图
//
之后，当用户选择在列表中查看联系人，你做第二次查询来获取标签的联系人和电话号码。
@覆盖
保护无效onListItemClick（ListView的L，视图V，INT位置，长的id）{
mCursor.moveToPosition（位置）;
startManagingCursor（mCursor）;
字符串的ContactID = mCursor.getString（mCursor.getColumnIndex（ContactsContract.Contacts._ID））;
光标phoneNumCursor = getContentResolver（）查询（Phone.CONTENT_URI，
空，Phone.CONTACT_ID +=？，新的String [] {}的ContactID，NULL）;
phoneNumCursor.moveToFirst（）;
矢量＆lt;串GT; phoneTypeList =新矢量＆lt;串GT;（）;
矢量＆lt;串GT; phoneNumberList =新矢量＆lt;串GT;（）;
而（！phoneNumCursor.isAfterLast（））{
整型= phoneNumCursor.getInt（phoneNumCursor.getColumnIndex（Phone.TYPE））;
phoneTypeList.add（将String.valueOf（Phone.getTypeLabel（getResources（），类型，）））;
phoneNumberList.add（phoneNumCursor.getString（phoneNumCursor.getColumnIndex（Phone.NUMBER）））;
phoneNumCursor.moveToNext（）;
}
//
//随意表明接触的标签和电话号码。 ^^
//
更新：
下面是一个例子，如果你想使用联系人选择器。
私有静态最终诠释CONTACT_PICKER_RESULT = 1001;
保护无效startContactPicker（）{
意图contactPickerIntent =新的意图（Intent.ACTION_PICK，Contacts.CONTENT_URI）;
startActivityForResult（contactPickerIntent，CONTACT_PICKER_RESULT）;
}
@覆盖
保护无效onActivityResult（INT申请code，INT结果code，意图数据）{
如果（结果code == RESULT_OK）{
开关（要求code）{
案例CONTACT_PICKER_RESULT：
光标光标= NULL;
字符串phoneNumber的=;
尝试 {
开放的结果= data.getData（）;
字符串ID = result.getLastPathSegment（）;
光标= getContentResolver（）查询（Phone.CONTENT_URI，
空，Phone.CONTACT_ID +=？，新的String [] {ID}，NULL）;
INT phoneIdx = cursor.getColumnIndex（Phone.DATA）;
如果（cursor.moveToFirst（））{
而（！cursor.isAfterLast（））{
phoneNumber的= cursor.getString（phoneIdx）;
//
//这将经过选择的联系人的所有phoneNumber的。
//
cursor.moveToNext（）;
}
}
}赶上（例外五）{
} 最后 {
如果（光标！= NULL）{
cursor.close（）;
}
numberView.setText（phoneNumber的）;
}
打破;
}
}
}
i managed to write add program that upon the user click a button, he will be able to retrieve a phone number that will fill an editText box. The problem is that if a contact has multiple numbers, it will always take the top most number.
I have been reading another thread , Getting Number from Contacts Picker, there is an answer, but i dont get it. As I am new to android programming, I'll appreciate if anyone out there could give me step by step instructions
Update
After trying , i found that this works. The only problem is , how do i display the phone type together with the phone number
public class Test extends Activity {
/** Called when the activity is first created. */
private static final int CONTACT_PICKER_RESULT=1001 ;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Button browse = (Button) findViewById(R.id.do_email_picker);
browse.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
// TODO Auto-generated method stub
Intent contactPickerIntent= new Intent (Intent.ACTION_PICK,Contacts.CONTENT_URI);
startActivityForResult(contactPickerIntent,CONTACT_PICKER_RESULT);
}
});
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
// TODO Auto-generated method stub
super.onActivityResult(requestCode, resultCode, data);
if(resultCode==RESULT_OK){
switch(requestCode){
case CONTACT_PICKER_RESULT:
//handle contact results
final EditText smsEntry = (EditText) findViewById(R.id.sms_to);
Cursor cursor = null;
String phoneNo = " ";
List<String> allNumbers = new ArrayList<String>();
int phoneIdx = 0;
try{
Uri result = data.getData();
Log.v("Akiff", "Got a contact result: "+ result.toString());
//get the contact id from the Uri
String id = result.getLastPathSegment();
//query for everything phone
cursor= getContentResolver().query(Phone.CONTENT_URI, null, Phone.CONTACT_ID + "=?", new String []{id} , null);
phoneIdx=cursor.getColumnIndex(Phone.DATA);
//let's just get every phone number
if(cursor.moveToFirst()){
while(cursor.isAfterLast()==false){
phoneNo =cursor.getString(phoneIdx);
allNumbers.add(phoneNo);
cursor.moveToNext();
}
}else{
Log.w("AKIFF", "No number");
Toast.makeText(Test.this, "This contact has no number", Toast.LENGTH_LONG).show();
}
}catch(Exception e){
Log.e("AKIFF", "error ",e);
}finally{
if(cursor!=null){
cursor.close();
}
final String [] items = allNumbers.toArray(new String[allNumbers.size() ]) ;
AlertDialog.Builder builder = new AlertDialog.Builder(Test.this);
builder.setTitle("Choose a number: ");
builder.setItems(items, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int item) {
// TODO Auto-generated method stub
String selectedNumber = items[item].toString();
selectedNumber = selectedNumber.replace("-","");
//selectedNumber = selectedNumber.replace("+","");
smsEntry.setText(selectedNumber);
}
});
AlertDialog alert = builder.create();
if(allNumbers.size()>1){
alert.show();
}else{
String selectedNumber= phoneNo.toString();
selectedNumber=selectedNumber.replace("-", "");
smsEntry.setText(selectedNumber);
}
if(phoneNo.length()==0){
Log.d("Akiff", "No contact");
}
}
break;
}
}else{
//gracefully handle failure
Log.w("Akiff","Warning activity not okay");
}
}
解决方案
First, you may need to query all contact in phone book.
// Run query
Uri uri = ContactsContract.Contacts.CONTENT_URI;
String[] projection = new String[] {
ContactsContract.Contacts._ID,
ContactsContract.Contacts.DISPLAY_NAME
};
String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP + " = '1'";
String[] selectionArgs = null;
String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";
// Build adapter with contact entries
Cursor mCursor = managedQuery(uri, projection, selection, selectionArgs, sortOrder);
//
// Bind mCursor to to your Listview
//
After that, when user select a contact in your list view, you make a second query to get label and number of that contact.
@Override
protected void onListItemClick(ListView l, View v, int position, long id) {
mCursor.moveToPosition(position);
startManagingCursor(mCursor);
String contactID = mCursor.getString(mCursor.getColumnIndex(ContactsContract.Contacts._ID));
Cursor phoneNumCursor = getContentResolver().query(Phone.CONTENT_URI,
null, Phone.CONTACT_ID + "=?", new String[] { contactID }, null);
phoneNumCursor.moveToFirst();
Vector<String> phoneTypeList = new Vector<String>();
Vector<String> phoneNumberList = new Vector<String>();
while (!phoneNumCursor.isAfterLast()){
int type = phoneNumCursor.getInt(phoneNumCursor.getColumnIndex(Phone.TYPE));
phoneTypeList.add(String.valueOf(Phone.getTypeLabel(getResources(),type,"")));
phoneNumberList.add(phoneNumCursor.getString(phoneNumCursor.getColumnIndex(Phone.NUMBER)));
phoneNumCursor.moveToNext();
}
//
// Feel free to show label and phone number of that contact. ^^
//
Updated:
Below is an example if you want to use Contact Picker.
private static final int CONTACT_PICKER_RESULT = 1001;
protected void startContactPicker(){
Intent contactPickerIntent = new Intent(Intent.ACTION_PICK,Contacts.CONTENT_URI);
startActivityForResult(contactPickerIntent, CONTACT_PICKER_RESULT);
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode == RESULT_OK) {
switch (requestCode) {
case CONTACT_PICKER_RESULT:
Cursor cursor = null;
String phoneNumber = "";
try {
Uri result = data.getData();
String id = result.getLastPathSegment();
cursor = getContentResolver().query(Phone.CONTENT_URI,
null, Phone.CONTACT_ID + "=?", new String[] { id }, null);
int phoneIdx = cursor.getColumnIndex(Phone.DATA);
if (cursor.moveToFirst()) {
while (!cursor.isAfterLast()){
phoneNumber = cursor.getString(phoneIdx);
//
// this will go through all phoneNumber of selected contact.
//
cursor.moveToNext();
}
}
} catch (Exception e) {
} finally {
if (cursor != null) {
cursor.close();
}
numberView.setText(phoneNumber);
}
break;
}
}
}
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