获取当前脚本在javascript中执行文件名 [英] Getting the current script executing filename in javascript

问题描述

好的，我一直在寻找这个问题已经太久了......我正在试图找出如何从javascript内部返回运行包含的javascript的页面的文件名。

Okay, I've been searching for this for way too long already... I'm trying to find out how I can return the filename of the page that's running an included javascript, from inside that javascript.

我可以使用 $ _ SERVER ['SCRIPT_FILENAME'] 轻松地在PHP中执行此操作，但在Javascript中这似乎是要困难得多。

I can easily do this in PHP using $_SERVER['SCRIPT_FILENAME'], but in Javascript this seems to be a lot harder.

我真的需要从 location.href 中对其进行子串，还是有更有效的方法？ jQuery能帮忙吗？

Do I really need to substring it from location.href or is there a more efficient way? Could jQuery help?

推荐答案

删除网址参数

function getFileName()
{
  var url = window.location.pathname;
  var lastUri = url.substring(url.lastIndexOf('/')+1);
  if(lastUri.indexOf('?')!= -1)
     return lastUri.substring(0,lastUri.indexOf('?'));
  else
     return lastUri;
}

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