如何检测：按两次相同的按键，但第二次按住2秒钟 [英] How to detect: Press twice the same key, but hold it the second time for 2 seconds

问题描述

如何检测：按两次相同的键，但第二次按住2秒？

How to detect: Press twice the same key, but hold it the second time for 2 seconds ?

我正在寻找一种检测keydown的有效方法键码37（左箭头）（或必要时的任何其他键）的事件，然后在释放键之后，在给定的延迟（如1秒）内，在相同的键码的第二次键控1.5或2秒内。

I'm looking for an efficient way to detect a keydown event for the keycode 37 (left arrow) (or any other key when necessary) and then a second keydown of the same keycode for 1.5 or 2 seconds just after releasing the key, Within a given delay, like 1 second.

这是回过头来看，不要混淆回去，在上一页上（这是我想要做的）和在这个之前继续元素，在同一个元素上页面

This is to go back without confusing between "Go back, on the previous page" (this is what i want to do) and "Go on the element before this one, on the same page"

我已经在$（document.ready（）标记中尝试使用old_keycode和old_keycode_timepressed以及new_keycode new_keycode_timepressed，但我需要复制/粘贴每个代码的完整代码我想要的密钥代码，代码本身效率不高。

I already tried with old_keycode and old_keycode_timepressed and new_keycode new_keycode_timepressed in the $(document.ready() tag, but I need to copy/paste the entire code for each keycode i want, and the code itself isn't efficient.

任何人都听说过一个可以帮助我的插件，或者有人愿意帮助我？

Anyone have heard of a plugin that can help me with that, or anyone is willing to help me whit it?

感谢您的时间。

推荐答案

jsFiddle演示

jsFiddle demo

var twice_37 = 0;

$(document).on('keyup', function( e ){

  if(e.which===37){         // If left arrow    

    if(twice_37===1){       // (remember that twice_37 is 0 initially)
      alert('Do something! (you pressed Left twice!)');
    }

    twice_37 = 1;          // Set to 1 and...
    setTimeout(function(){ // ...reset to 0 after 1s
      twice_37 = 0; 
    }, 1000);

  }

});

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