chunk /在Javascript中拆分字符串而不会破坏单词 [英] chunk/split a string in Javascript without breaking words

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问题描述

美好的一天,



我想知道是否有一种简单的方法可以在不破坏单词的情况下分块/分割字符串。



例如:

  var input =Lorem ipsum dolor sit amet,consectetur adipiscing elit.Proin placerat nisi nec vulputate scelerisque,metus lectus ultricies massa,et luctus elit libero eu erat.Fusce vitae sem lacus,eu ullamcorper lectus.Lorem ipsum dolor sit amet,consectetur adipiscing elit。; 

如果我突破 80个字符,应该返回这样的数组:

  var output = [Lorem ipsum dolor sit amet,consectetur adipiscing elit.Proin placerat,nisi,
nec vulputate scelerisque,metus lectus ultricies massa,et luctus elit libero,
eu erat.Fusce vitae sem lacus,eu ullamcorper lectus.Lorem ipsum dolor sit,
amet,consectetur adipiscing elit。 ]。

我发现这段代码非常好:

  //http://phpjs.org/functions/chunk_split:369 
function chunk_split(body,chunklen,end){
//返回分割线
//
//版本:1103.1210
//讨论于:http://phpjs.org/functions/chunk_split
// +原文:Paulo Freitas
// +输入:Brett Zamir(http://brett-zamir.me)
// + bugfixed by:Kevin van Zonneveld(http://kevin.vanzonneveld.net)
// +改进:Theriault
// *示例1:chunk_split('Hello world!',1,'*');
// *返回1:'H * e * l * l * o * * w * o * r * l * d *!*'
// *示例2:chunk_split('Hello world !',10,'*');
// *返回2:'Hello worl * d!*'
chunklen = parseInt(chunklen,10)|| 76;
end = end || \r\\\
;

if(chunklen< 1){
返回false;
}

返回body.match(new RegExp(。{0,+ chunklen +},g))。join(end);
}

但我真的怀疑我可以修改它所以不会把话语分成两半。任何提示?



谢谢!

解决方案

这样的东西?

  var n = 80; 

while(n){
if(input [n ++] ==''){
break;
}
}

output = input.substring(0,n).split('');
console.log(输出);

更新



<现在我重新阅读了这个问题,这是一个更新的解决方案:

  var len = 80; 
var curr = len;
var prev = 0;

output = [];

while(输入[curr]){
if(input [curr ++] ==''){
output.push(input.substring(prev,curr));
prev = curr;
curr + = len;
}
}
output.push(input.substr(prev));


Good day,

I would like to know if there is an easy way to chunk/split a string without breaking the words.

Eg:

var input = "Lorem ipsum dolor sit amet, consectetur  adipiscing elit. Proin placerat, nisi nec vulputate scelerisque, metus lectus ultricies massa, et luctus elit libero eu erat. Fusce vitae sem lacus, eu ullamcorper lectus. Lorem ipsum dolor sit amet, consectetur adipiscing elit.";

Should return an array like this if I break at 80 characters long:

var output = ["Lorem ipsum dolor sit amet, consectetur  adipiscing elit. Proin placerat, nisi",
"nec vulputate scelerisque, metus lectus ultricies massa, et luctus elit libero",
"eu erat. Fusce vitae sem lacus, eu ullamcorper lectus. Lorem ipsum dolor sit",
"amet, consectetur adipiscing elit."];

I found that really nice piece of code:

//http://phpjs.org/functions/chunk_split:369
function chunk_split (body, chunklen, end) {
    // Returns split line  
    // 
    // version: 1103.1210
    // discuss at: http://phpjs.org/functions/chunk_split
    // +   original by: Paulo Freitas
    // +      input by: Brett Zamir (http://brett-zamir.me)
    // +   bugfixed by: Kevin van Zonneveld (http://kevin.vanzonneveld.net)
    // +   improved by: Theriault
    // *     example 1: chunk_split('Hello world!', 1, '*');
    // *     returns 1: 'H*e*l*l*o* *w*o*r*l*d*!*'
    // *     example 2: chunk_split('Hello world!', 10, '*');
    // *     returns 2: 'Hello worl*d!*'
    chunklen = parseInt(chunklen, 10) || 76;
    end = end || '\r\n';

    if (chunklen < 1) {
        return false;
    }

    return body.match(new RegExp(".{0," + chunklen + "}", "g")).join(end);
}

But I really doubt I can modify it so words aren't broken in half. Any tips?

Thank you!

解决方案

Something like this?

var n = 80;

while (n) { 
    if (input[n++] == ' ') { 
        break;  
    } 
}

output = input.substring(0,n).split(' ');
console.log(output);

UPDATED

Now that I re-read the question, here's an updated solution:

var len = 80;
var curr = len;
var prev = 0;

output = [];

while (input[curr]) {
    if (input[curr++] == ' ') {
        output.push(input.substring(prev,curr));
        prev = curr;
        curr += len;
    }
}
output.push(input.substr(prev));  

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