JavaScript负面的后视问题 [英] JavaScript negative lookbehind issue

问题描述

我有一些JavaScript在Amazon链接中查找Amazon ASIN，例如

I've got some JavaScript that looks for Amazon ASINs within an Amazon link, for example

http://www.amazon.com/dp/B00137QS28

<为此，我使用以下正则表达式： /（[A-Z0-9] {10}）

但是，我不希望它匹配艺术家链接，如下所示：

However, I don't want it to match artist links which look like:

http://www.amazon.com/Artist-Name/e/B000AQ1JZO

所以我需要排除任何在斜杠前面有一个'/ e'和10个字符的字母数字代码的链接。我认为以下内容会这样做：（？<！/ e）（[A-Z0-9] {10}），但结果却是负面的看法用JavaScript工作。是对的吗？有没有另一种方法可以做到这一点？

So I need to exclude any links where there's a '/e' before the slash and the 10-character alphanumeric code. I thought the following would do that: (?<!/e)([A-Z0-9]{10}), but it turns out negative lookbehinds don't work in JavaScript. Is that right? Is there another way to do this instead?

非常感谢任何帮助！

作为旁注，请注意有很多亚马逊链接格式，这就是我想黑名单而不是白名单的原因，例如，这些都是同一页：

As a side note, be aware there are plenty of Amazon link formats, which is why I want to blacklist rather than whitelist, eg, these are all the same page:

http://www.amazon.com/gp/product/B00137QS28/
http://www.amazon.com/dp/B00137QS28
http://www.amazon.com/exec/obidos/ASIN/B00137QS28/
http://www.amazon.com/Product-Title-Goes-Here/dp/B00137QS28/

推荐答案

在你的情况下，这样的表达式可以起作用：

In your case an expression like this would work:

/(?!\/e)..\/([A-Z0-9]{10})/

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