如何在不使用指针的情况下传输地址值 [英] How to transfer an address value without using pointers
问题描述
我有以下程序结构:
main
.....
int A = 5;
int * ptr = A; (所以此时ptr存储A的地址)
.....
.....
send_data(... )
....
.....
函数send_data,我需要在它的身上使用地址
A:
void send_data(...){
.....
.....
char * R =(char *)ptr;
......
但是由于编译器的限制(请不要问我为什么:))
我不能在这里使用指针。
目前我还不知道如何发送到函数地址
信息,有人有想法吗?
提前谢谢
Hi,
I have the following program structure:
main
.....
int A=5;
int* ptr= A; (so at this point ptr stores address of A)
.....
.....
send_data(...)
....
.....
for the function send_data, I need on its body to use the address of
A:
void send_data(...){
.....
.....
char* R=(char*) ptr;
......
but due to the limitations of the compiler (please dont ask me why :))
I can not use pointers here.
At the moment I do not know how to send to the function the address
information, somebody has idea ?
Thanks in advance
推荐答案
6月16日晚上10点39分,Horacius ReX< horacius .... @ gmail.comwrote:
On Jun 16, 10:39 pm, Horacius ReX <horacius....@gmail.comwrote:
我有以下程序结构:
main
....
int A = 5;
int * ptr = A; (所以此时ptr存储A的地址)
Hi,
I have the following program structure:
main
....
int A=5;
int* ptr= A; (so at this point ptr stores address of A)
不是你的意思和A?
Don''t you mean &A?
....
....
send_data(...)
....
....
send_data(...)
send_data?
send_data?
...
....
函数send_data,我需要在它的身体上使用地址
A:
void send_data(...){
....
....
char * R =(char *)ptr;
.....
但由于编译器的限制(请不要问我为什么:))
我不能在这里使用指针。
...
....
for the function send_data, I need on its body to use the address of
A:
void send_data(...){
....
....
char* R=(char*) ptr;
.....
but due to the limitations of the compiler (please dont ask me why :))
I can not use pointers here.
为什么?
Why?
目前我不知道如何向函数发送地址
信息,有人有想法吗?
At the moment I do not know how to send to the function the address
information, somebody has idea ?
您可以定义ptr属于全局范围。
You can define ptr to belong to the global scope.
6月16日20:39, Horacius ReX< horacius .... @ gmail.comwrote:
On 16 Jun, 20:39, Horacius ReX <horacius....@gmail.comwrote:
但是由于编译器的限制(请不要问我为什么:))
我不能在这里使用指针。
but due to the limitations of the compiler (please dont ask me why :))
I can not use pointers here.
如果你解释为什么你不能使用
指针,你可能会得到更好的答案。这是编译器的问题还是你的理解
的编译器?
You may well get better answers if you explain why you can''t use
pointers. Is it a problem with the compiler or with your understanding
of the compiler?
Horacius ReX写道:
Horacius ReX wrote:
我有以下程序结构:
main
....
int A = 5;
int * ptr = A; (所以此时ptr存储地址为A)
Hi,
I have the following program structure:
main
....
int A=5;
int* ptr= A; (so at this point ptr stores address of A)
编号你想:
int * ptr =& A;
No. You want:
int *ptr = &A;
....
....
send_data(...)
...
....
函数send_data,我需要在它的主体上使用
A:
void send_data(...){
....
....
char * R =(char *)ptr;
.....
....
....
send_data(...)
...
....
for the function send_data, I need on its body to use the address of
A:
void send_data(...){
....
....
char* R=(char*) ptr;
.....
这指定给R通过将
ptr的内容解释为char *值得出的值。
This assigns to R the value derived from interpreting the contents of
ptr as a char * value.
但由于编译器的限制(请不要问我为什么:))
我不能在这里使用指针。
目前我不知道如何向函数发送地址
信息,有人有想法吗?
提前付款
but due to the limitations of the compiler (please dont ask me why :))
I can not use pointers here.
At the moment I do not know how to send to the function the address
information, somebody has idea ?
Thanks in advance
如果你的系统有限,那么你可能tr y将地址存储在
中一个适当的整数对象。如果你的系统有他们使用intptr_t或
uintptr_t。
If your system is this limited then you might try storing the address in
a appropriate integer object. If your system has them use intptr_t or
uintptr_t.
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