BCD列表到HEX列表 [英] BCD List to HEX List

问题描述

我正在寻找一个可以转换列表的算法，例如：


我正在使用用于原型算法的python：这将转移到嵌入式
系统中的C，其中int有16位 - 我不想使用任何python库。


l1 = [1,2,3,4,6,7,8]＃表示十进制数12345678

l2 = func（l1）

＃l2 = [0x1,0x2,0xD，0x6,0x8,0x7] #represents 0x12D687

问候，


Philippe

Hi,

I''m looking for an algo that would convert a list such as:

I''m using python to prototype the algo: this will move to C in an embedded
system where an int has 16 bits - I do not wish to use any python library.

l1 = [1,2,3,4,6,7,8] #represents the decimal number 12345678
l2 = func (l1)
# l2 = [0x1, 0x2, 0xD, 0x6, 0x8, 0x7] #represents 0x12D687
Regards,

Philippe

推荐答案

在< 5S8zg.1553

In <5S8zg.1553

W93.658@dukeread05> ;, Philippe Martin写道：

W93.658@dukeread05>, Philippe Martin wrote:

我正在寻找能够转换列表的算法，例如：


我正在使用python来构建算法原型：这将会移动在嵌入式
系统中，C为16位 - 我不希望使用任何python库。


l1 = [1,2， 3,4,6,7,8]＃表示t十进制数12345678

l2 = func（l1）

＃l2 = [0x1,0x2,0xD，0x6,0x8,0x7] #represents 0x12D687

I''m looking for an algo that would convert a list such as:

I''m using python to prototype the algo: this will move to C in an embedded
system where an int has 16 bits - I do not wish to use any python library.

l1 = [1,2,3,4,6,7,8] #represents the decimal number 12345678
l2 = func (l1)
# l2 = [0x1, 0x2, 0xD, 0x6, 0x8, 0x7] #represents 0x12D687

def func（x）：

result = list（x）

result [2：4] = [0xd]

结果[-1]，结果[-2] =结果[-2]，结果[-1]

返回结果


l1 = [1,2,3,4,6,7,8]

l2 = func（l1）

print l2

>
现在请把问题描述得更好一些。 ;-)


Ciao，

Marc''BlackJack''Rintsch

def func(x):
result = list(x)
result[2:4] = [0xd]
result[-1], result[-2] = result[-2], result[-1]
return result

l1 = [1, 2, 3, 4, 6, 7, 8]
l2 = func(l1)
print l2

And now please describe you problem a little better. ;-)

Ciao,
Marc ''BlackJack'' Rintsch

Marc'' BlackJack''Rintsch写道：

Marc ''BlackJack'' Rintsch wrote:

In< 5S8zg.1553

In <5S8zg.1553

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