忘记密码无法正常工作...... [英] forget password can't function...

问题描述

下面是我的忘记密码，为什么不能正常工作？当我点击提交按钮时，它仍然保留在同一页面上，就像我没有点击任何东西一样......


[PHP]<？php

if（$ go ==" 1"）

{

mysql_connect（" localhost"，" root"，""） ;

mysql_select_db（" ums电子工作门户网站）;

$ sql = @mysql_query（" SELECT * FROM company WHERE username ='' $ username''&& emailAdd =''$ email''"）;

if（！$ sql）

{

echo用户名和电子邮件地址不匹配。;

退出;

}

$ query = mysql_query（$ sql ）;

$ fPass = mysql_fetch_array（$ query）;


$ to =" SELECT * FROM company WHERE emailAdd =''$ email''" ;;

$ subject ="您的密码" ;;

$ body =" SELECT * FROM company WHERE username =''$ username''&& password =''$ password''" ;;

$ headers =" from：[e-mail]\\\
" ;;


mail（ $ to，$ subject，$ body，$ headers）;

echo"您的密码已发送至$ to" ;;

}

？> [/ PHP]


[HTML]< form action ="<？= $ PHP_SELF？>" method =" post">

用户名：< input type =" text"命名= QUOT;用户名"大小= QUOT; 24英寸; border =" 0">< br>

电子邮件：< input type =" text"名称= QUOT;电子邮件"大小= QUOT; 24英寸; border =" 0">< br>

< input type =" hidden"命名= QUOT;去"值= QUOT 1 QUOT; border =" 0">< input type =" submit"名称= QUOT; submitButtonName" border =" 0">

< / form [/ HTML]>

解决方案

go ==" 1" ）

{

mysql_connect（" localhost"，" root"，""）;

mysql_select_db（" ums e -job portal"）;

sql = @mysql_query（" SELECT * FROM company WHERE username =''

< blockquote> username''&&& emailAdd =''

Below is my forget password, why cannot function?? When i click on the submit button, it still remain on the same page and just like i didn''t click anything...

[PHP]<?php
if($go == "1")
{
mysql_connect("localhost","root","");
mysql_select_db("ums e-job portal");

$sql = @mysql_query("SELECT * FROM company WHERE username=''$username'' && emailAdd=''$email'' ");
if(!$sql)
{
echo "The username and email address do not match.";
exit;
}
$query = mysql_query($sql);
$fPass = mysql_fetch_array($query);

$to = "SELECT * FROM company WHERE emailAdd=''$email'' ";
$subject = "Your Password";
$body = "SELECT * FROM company WHERE username=''$username'' && password=''$password'' ";
$headers = "From: [e-mail]\n";

mail($to, $subject, $body, $headers);
echo "Your Password has been sent to $to";
}
?>[/PHP]

[HTML]<form action="<?= $PHP_SELF ?>" method="post">
Username: <input type="text" name="username" size="24" border="0"><br>
E-mail: <input type="text" name="email" size="24" border="0"><br>
<input type="hidden" name="go" value="1" border="0"><input type="submit" name="submitButtonName" border="0">
</form[/HTML]>

解决方案

go == "1")
{
mysql_connect("localhost","root","");
mysql_select_db("ums e-job portal");

sql = @mysql_query("SELECT * FROM company WHERE username=''

username'' && emailAdd=''

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