位模式问题 [英] Bit Pattern Problem
问题描述
大家好。感谢有关qudratic方程问题的帮助......我没想到实际上在做数学......哎呀。无论如何...我是
在让以下程序工作时遇到一些麻烦。我想从基数为10的输入中输出一个位模式。
输入之后，我得到的只是零...我已查看代码但看不到问题...任何想法？
/ *显示对应于
a带符号十进制整数的位模式* /
#include< stdio.h>
#include< ; stdlib.h>
int main（无效）
{
int a，b，m，count，nbits;
无符号掩码;
/ *以位为单位确定字大小并设置初始掩码* /
nbits = 8 * sizeof（int）;
m = 0x1<< （nbits - 1）; / *将1放在最左边的位置* /
/ *主循环* /
做{
/ *读一个签名整数* /
printf（" \ n\\\
输入一个整数值（0表示停止）："，a）;
scanf（"％d" ;，& a）;
/ *输出位模式* /
mask = m;
for（count = 1; count< = nbits; count ++）; {
b =（a& mask）？ 1：0; / *打开或关闭显示位* /
printf（"％x"，b）; / *打印显示位* /
if（count％4 == 0）
printf（""）; / *第4位后的空格* /
mask>> = 1; / *移动掩码1位置向右* /
}
} while（a！= 0）;
返回EXIT_SUCCESS; / *如果它在那里为什么不使用它的人！ * /
}
Hi Everyone. Thanks for the help with the qudratic equation problem...I
didn''t think about actually doing the math...whoops. Anyway... I''m
having some trouble getting the following program to work. I want to
output a bit pattern from base 10 input. All I get is a zero after the
input...I''ve looked over the code but can''t see the problem...any ideas?
/* display the bit pattern corresponding to
a signed decimal integer */
#include<stdio.h>
#include<stdlib.h>
int main(void)
{
int a, b, m, count, nbits;
unsigned mask;
/* determine the word size in bits and set the initial mask */
nbits = 8 * sizeof(int);
m = 0x1 << (nbits - 1); /* Place 1 in leftmost position */
/* main loop */
do {
/* read a signed integer */
printf("\n\nEnter an integer value (0 to stop): ", a);
scanf("%d", &a);
/* output the bit pattern */
mask = m;
for(count = 1; count <= nbits; count++); {
b = (a & mask) ? 1 : 0; /* set display bit on or off */
printf("%x", b); /* print display bit */
if (count % 4 == 0)
printf(" "); /* blank space after ever 4th digit */
mask >>= 1; /* shift mask 1 position to the right */
}
} while (a != 0);
return EXIT_SUCCESS; /* If it''s there why not use it people! */
}
推荐答案
fb写道：
nbits = 8 * sizeof（int）;
nbits = 8 * sizeof(int);
错误在这一行。
-
Derrick Coetzee
我将此新闻组发布到公共域。我不承担所有
明示或暗示保证并承担所有责任。我不是专业人士。
The error is on this line.
--
Derrick Coetzee
I grant this newsgroup posting into the public domain. I disclaim all
express or implied warranty and all liability. I am not a professional.
Derrick Coetzee写道：
Derrick Coetzee wrote:
fb写道：
fb wrote:
nbits = 8 * sizeof（int）;
nbits = 8 * sizeof(int);
错误在这一行。
The error is on this line.
对 - 谢谢。
right-o thanks.
Derrick Coetzee写道：
Derrick Coetzee wrote:
fb写道：
fb wrote:
nbits = 8 * sizeof（int）;
错误在这一行。
nbits = 8 * sizeof(int);
The error is on this line.
哎呀， 不，这不对。我是个白痴。实际错误在这一行：
for（count = 1; count< = nbits; count ++）; {
Oops, no it''s not. I''m an idiot. The actual error is on this line:
for(count = 1; count <= nbits; count++); {
注意那些意外的分号！ ^
-
Derrick Coetzee
我将此新闻组发布到公共领域。我不承担所有
明示或暗示保证并承担所有责任。我不是专业人士。
Watch out for those accidental semicolons! ^
--
Derrick Coetzee
I grant this newsgroup posting into the public domain. I disclaim all
express or implied warranty and all liability. I am not a professional.
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