c中是否有比双倍更大的数据类型？ [英] Is there a bigger data type in c than the double one?
问题描述
C中的数据类型是否比双（64位）的数据类型更好？
或旧的长双（80位）？
我'我想在我的数学应用程序中添加精度，但是我无法想象
如何。
非常感谢。
Is there a bigger, mathematical, data type in C than the double (64 bit) one
or the old long double (80 bit)?
I''d like to add precision to my mathematical application, but I can''t figure
out how.
Thanks alot.
推荐答案
>在C中是否存在比双（64位）
>Is there a bigger, mathematical, data type in C than the double (64 bit) one
或旧的长双（80位）更大的数学数据类型？
C双打不保证是64位。
long double不保证是80位，为什么它是* OLD *
long double？
您是否使用超过80位的浮点硬件
来表示一个数字？
我想为我的数学应用程序添加精度，但我无法确定如何。
or the old long double (80 bit)?
C doubles are not guaranteed to be 64 bits.
long double is not guaranteed to be 80 bits, and why is it the *OLD*
long double?
Do you have floating-point hardware that uses more than 80 bits
to represent a number?
I''d like to add precision to my mathematical application, but I can''t figure
out how.
一个int可以想象是128位，但如果你的机器有128位的操作，那么128位整数类型很可能很长。
Gordon L .Burditt
An int could conceivably be 128 bits, although if your machine has
128-bit operations, the 128-bit integer type is more likely long long.
Gordon L. Burditt
" Gordon Burditt" <去*********** @ burditt.org> ha scritto nel messaggio
news：co ******** @ library1.airnews.net ...
"Gordon Burditt" <go***********@burditt.org> ha scritto nel messaggio
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是否有一个更大的数学数据类型C比双（64位）
一个旧的长双（80位）？
Is there a bigger, mathematical, data type in C than the double (64 bit) oneor the old long double (80 bit)?
C双打不保证是64比特。
long double不保证是80位，为什么它是* OLD *
长的双倍？
你有浮点硬件使用超过80位
代表一个数字？
C doubles are not guaranteed to be 64 bits.
long double is not guaranteed to be 80 bits, and why is it the *OLD*
long double?
Do you have floating-point hardware that uses more than 80 bits
to represent a number?
我想在我的数学应用程序中添加精度，但我不能用b $ b来计算。
I''d like to add precision to my mathematical application, but I can''t figureout how.
一个int可以想象是128位，但如果你的机器有128位操作，128位整数类型更可能很长。
Gordon L. Burditt
An int could conceivably be 128 bits, although if your machine has
128-bit operations, the 128-bit integer type is more likely long long.
Gordon L. Burditt
我的机器是使用Windowsme的p4 pc;
我想在结果示例中添加小数而不是
17位小数30或40.
My machine is a p4 pc using Windowsme;
I would like to add decimals to my results example instead of
17 decimals 30 or 40.
Daniel Fadlun写道：
Daniel Fadlun wrote:
" Gordon Burditt" <去*********** @ burditt.org> ha scritto nel messaggio
新闻：co ******** @ library1.airnews.net ...
"Gordon Burditt" <go***********@burditt.org> ha scritto nel messaggio
news:co********@library1.airnews.net...
是否有一个更大的，数学的，数据类型的C比双（64位）
或旧的长双（80位）？
Is there a bigger, mathematical, data type in C than the double (64 bit)
one
or the old long double (80 bit)?
C双打是不保证是64位。
long double不保证是80位，为什么它是* OLD *
长的双倍？
你有浮点吗？使用超过80位的硬件代表一个数字？
C doubles are not guaranteed to be 64 bits.
long double is not guaranteed to be 80 bits, and why is it the *OLD*
long double?
Do you have floating-point hardware that uses more than 80 bits
to represent a number?
我想为我的数学应用添加精度，但我可以''图
如何。
I''d like to add precision to my mathematical application, but I can''t
figure
out how.
一个int可以想象是128位，但如果你的机器有128位操作，128-比特整数类型更可能很长。
Gordon L. Burditt
An int could conceivably be 128 bits, although if your machine has
128-bit operations, the 128-bit integer type is more likely long long.
Gordon L. Burditt
我的机器是使用Windowsme的p4 pc;
我想将小数添加到我的结果示例中而不是o f
17位小数30或40。
My machine is a p4 pc using Windowsme;
I would like to add decimals to my results example instead of
17 decimals 30 or 40.
这是100-133个有效位数。 H /格式数字
VAX可以接近低端（我不记得只是
它的128位中有多少是指数），但我''我不知道
任何使用H格式的C编译器。
但是，最大的问题是为什么你想要这么多？ />
位数？您可以在小数点后四十位分配一个加号或者减号
的一个波动是什么意思？如果你想要计算Angstrom中的宇宙半径
单位，那么四十个地方远远超过你的需要。
-
Er ********* @ sun.com
That''s 100-133 significand bits. H-format numbers on
the VAX could approach the lower end (I don''t recall just
how many of its 128 bits were exponent), but I''m not aware
of any C compiler that made use of H-format.
The big question, though, is why do you want so many
digits? What meaning could you assign to a plus-or-minus
one fluctuation in the fortieth decimal place? If you''re
trying to calculate the radius of the Universe in Angstrom
units, forty places are far more than you need.
--
Er*********@sun.com
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