Judagrali系列：问题。 [英] A Judagrali series: problem.

问题描述

Judagrali系列：

找到第4个素数N，使得N = NumberOfDigits（Q）其中N是素数且Q是

素数且其中Q = 2p -1其中P是素数。

示例第一素数N是2，因为2 = NumberOfDigits（31）因为2是素数而且

因为31 = 2 ^ 5 -1和因为5是素数。

我们正在寻找Judagrali系列中的第2，第3，第4素数N以及它的相应Q和P值的
。

提示：

1第4个N对应一个非常大的M.​​在进行

计算时考虑到这一点。

2计算效率很重要。

3必须使用面向对象和继承。即N是素数，Q的子集是
（子类），Q也是素数，P的子集也是素数。

解决方案

一个Judagrali系列：

找到第四个素数N，使得N = NumberOfDigits（Q）其中N是素数且Q是

素数且其中Q = 2p-1其中P为素数。

示例第一素数N为2，因为2 = NumberOfDigits（31）因为2是素数且

因为31 = 25-1而因为5是素数。

我们正在寻找Judagrali系列中的第2，第3，第4素数N以及它的

对应的Q和P值。

提示：

1第4 N对应一个非常大的M.​​在做
计算。

2计算效率很重要。

3必须使用面向对象和继承。即，N是素数，Q的子集是
（子类），Q也是素数，而P的子集也是素数。

这看起来不合适。你有

因为31 = 25-1因为5是素数。

这可能不正确。

看起来不对这里。你有



那是不正确的。

它是2到5而不是25

所以Q =（2 ^ p） - 1？

A Judagrali series:
Find the 4th prime number N such that N=NumberOfDigits(Q) where N is prime AND Q is
prime AND where Q=2p-1 where P is prime.
Example the 1st prime number N is 2, because 2=NumberOfDigits(31) because 2 is prime and
because 31=2^5-1 and because 5 is prime.
We are looking for the 2nd,3rd, 4th prime number N in the Judagrali series as well as its
corresponding Q and P values.
Hints:
1 The 4th N corresponds to a very large M. Take this into account when doing the
calculation.
2 Computational efficiency is important.
3 Object orientation and inheritance MUST be used. i.e. N is a prime, and a subset
(subclass) of Q, Q is also prime and a subset of P which is also prime.

解决方案

A Judagrali series:
Find the 4th prime number N such that N=NumberOfDigits(Q) where N is prime AND Q is
prime AND where Q=2p-1 where P is prime.
Example the 1st prime number N is 2, because 2=NumberOfDigits(31) because 2 is prime and
because 31=25-1 and because 5 is prime.
We are looking for the 2nd,3rd, 4th prime number N in the Judagrali series as well as its
corresponding Q and P values.
Hints:
1 The 4th N corresponds to a very large M. Take this into account when doing the
calculation.
2 Computational efficiency is important.
3 Object orientation and inheritance MUST be used. i.e. N is a prime, and a subset
(subclass) of Q, Q is also prime and a subset of P which is also prime.

Doesn''t look right here. You''ve got

because 31=25-1 and because 5 is prime.

That cannot be correct.

Doesn''t look right here. You''ve got


That cannot be correct.

it is 2 to the power 5 not 25

So Q = (2^p) - 1 ?

这篇关于Judagrali系列：问题。的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！