如何将__int64传递给unsigned char [16] [英] how pass an __int64 to unsigned char [16]
问题描述
我有一个结构allmsg和他的成员：
Hi,
I have a struct "allmsg" and him member :
推荐答案
好的，
所以要恢复我之前写的所有内容。
我有这个结构：
Ok,
So for resuming all I wrote before.
I have this struct :
struct frame_message {
// typedef struct {
unsigned int sender_id;
unsigned int encrypt_key_id;
unsigned int encrypt_size;
unsigned int crc ;
unsigned int data_length;
unsigned int sequence_number;
unsigned int packet_type;
unsigned int read_number;
unsigned char card_number [16] ; /////
unsigned int pin_code;
unsigned char padding_bytes [MAX_PADDING];
} allmsg;
struct frame_message {
//typedef struct {
unsigned int sender_id;
unsigned int encrypt_key_id;
unsigned int encrypt_size;
unsigned int crc;
unsigned int data_length;
unsigned int sequence_number;
unsigned int packet_type;
unsigned int read_number;
unsigned char card_number[16];/////
unsigned int pin_code;
unsigned char padding_bytes[MAX_PADDING];
}allmsg;
我传给allmsg.card_number一个_int64，但这不是好办法
And I pass to allmsg.card_number an _int64 but it is not good way
fonction pass（_int64 badgeid）
{
allmsg.card_number =（unsigned char *）& badgeid; // erreur不兼容的signes assignement of（unsigned char * to unsigned char [16]
...
}
fonction pass(_int64 badgeid)
{
allmsg.card_number=(unsigned char*)&badgeid; //erreur incompatible signes assignement of (unsigned char* to unsigned char [16]
...
}
你能解决我吗？
谢谢
Could you fix me please ?
Thank you
__ int64是8个字节很长，所以我不明白为什么你要用8字节数填充一个16字节的数组？除非你想做这样的事情：
__int64 is 8 bytes long,so I don''t see why are you trying to fill a 16byte array with 8 byte number?Unless you want to do something like this:
谢谢Savage，
确切地说，我想要：_int64中的包含必须是s card_number [16]中的ame（但以字节为单位）格式。
例如，当我显示变量的符号时：
Thank you Savage,
Exactly, I want : the contain in _int64 must be the same (but in bytes) format in card_number[16] .
For example when I display containt of my variables:
//（tempfadge_id的printf）
数据：CARD NUMBER = 123456789
//（printf for allmsg.card_number []）
0 [0x00]，1 [0x00]，2 [0x00]，3 [0x00]，4 [0xB7]，5 [0xFA]，6 [0x09]，7 [0xC8]，8 [ 0x00]，9 [0x00]，10 [0x00]，11 [0x00]，12 [0x07]，13 [0x5B]，14 [0xCD]，
15 [0x15]，
//(printf of temp_badge_id )
data: CARD NUMBER = 123456789
//(printf for of allmsg.card_number[] )
0[0x00], 1[0x00], 2[0x00], 3[0x00], 4[0xB7], 5[0xFA], 6[0x09], 7[0xC8], 8[0x00], 9[0x00], 10[0x00], 11[0x00], 12[0x07], 13[0x5B], 14[0xCD],
15[0x15],
就像你看到long long int：十六进制的123456789是75BCD15（字节12 - > 15）
但含有byes 4 - > 7 ??奇怪
我认为问题来自此处：
Like you see long long int: 123456789 in hex is 75BCD15 (bytes 12 -> 15 )
but what is contain of byes 4 -> 7 ?? strange
I think that problems come before from here:
allmsg.card_number [15] = ptemp_badge_id [15];
allmsg.card_number [14] = ptemp_badge_id [14];
...
..
allmsg.card_number [0] = ptemp_badge_id [0];
allmsg.card_number[15]=ptemp_badge_id[15];
allmsg.card_number[14]=ptemp_badge_id[14];
...
..
allmsg.card_number[0]=ptemp_badge_id[0];
但是我不确定？
所以也许iproblem正确地将__int64传递给16字节的unsigned char []
谢谢
But I''m not sure ?
So maybe iproblem is to pass correctly __int64 to unsigned char [] of 16 bytes
Thank you
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