滥用C / C ++评论 [英] Abusing C/C++ comments
问题描述
大家好，
我记得几年前我看过一段代码，它使用了两个/ * *的
组合/和//这样你就可以确定源代码的
编译类型。我不记得究竟是什么发生了什么，但是我认为它就像是源代码是由交流编译器编译的
变量的值变为1如果
它是用c ++编译器编译的，那么这个值就变成了0.你知道怎么用
我能找到它吗？
任何想法？
提前致谢，
Hello all,
I remember that I saw a piece of code a few years ago, it was using a
combination of both /* */ and // such that you could determine the
compile type of the source code. I don''t remember exactly what was
happening, but I assume it was something like if the source code was
being compiled by a c compiler the value of a variable became 1 and if
it was compiled with c++ compiler the value became 0. Do you know how
can I find that ?
Any ideas ?
Thanks in advance,
推荐答案
Hapary < ha **** @ gmail.com在留言中写道
news：11 ********************* @ y80g2000hsf.googlegro ups .com ...
"Hapary" <ha****@gmail.comwrote in message
news:11*********************@y80g2000hsf.googlegro ups.com...
Hello all，
我记得几年前我看过一段代码，它使用了/ * * /和//的组合
，这样就可以确定源代码的
编译类型。我不记得究竟是什么发生了什么，但是我认为它就像是源代码是由交流编译器编译的
变量的值变为1如果
它是用c ++编译器编译的，那么该值就变为0.你知道如何找到
吗？
Hello all,
I remember that I saw a piece of code a few years ago, it was using a
combination of both /* */ and // such that you could determine the
compile type of the source code. I don''t remember exactly what was
happening, but I assume it was something like if the source code was
being compiled by a c compiler the value of a variable became 1 and if
it was compiled with c++ compiler the value became 0. Do you know how
can I find that ?
/ * * /是一个合法的C ++注释，而//不是C中的合法序列.C ++
注释互相评论。我无法想到实现这一目标的方法。
标准的，可接受的方式是使用为此目的提供的#ifdef __cplusplus构造
。
-
免费游戏和编程好东西。
http://www.personal.leeds.ac.uk/~bgy1mm
/* */ is a legal C++ comment whilst // is not a legal sequence in C. C++
comments comment each other out. I can''t think of a way to achieve this.
The standard, acceptable way is to use the #ifdef __cplusplus construct
provided for the purpose.
--
Free games and programming goodies.
http://www.personal.leeds.ac.uk/~bgy1mm
Malcolm McLean写道：
Malcolm McLean wrote:
>
" Hapary" < ha **** @ gmail.com在留言中写道
news：11 ********************* @ y80g2000hsf.googlegro ups .com ...
>
"Hapary" <ha****@gmail.comwrote in message
news:11*********************@y80g2000hsf.googlegro ups.com...
> Hello all，
我记得几年前我看过一段代码，它是使用/ * * /和//的组合，以便确定源代码的编译类型。我不记得到底发生了什么，但我认为这就像是如果源代码是由ac编译器编译的，变量的值变为1并且如果
它是用c ++编译器编译的，值变为0.你知道我怎么能找到它吗？
>Hello all,
I remember that I saw a piece of code a few years ago, it was using a
combination of both /* */ and // such that you could determine the
compile type of the source code. I don''t remember exactly what was
happening, but I assume it was something like if the source code was
being compiled by a c compiler the value of a variable became 1 and if
it was compiled with c++ compiler the value became 0. Do you know how
can I find that ?
/ * * /是一个合法的C ++评论，而/ /不是C中的合法序列。
/* */ is a legal C++ comment whilst // is not a legal sequence in C.
它是在C99。
-
Ian Collins。
It is in C99.
--
Ian Collins.
" Malcolm McLean" < re ******* @ btinternet.comwrites：
"Malcolm McLean" <re*******@btinternet.comwrites:
" Hapary" < ha **** @ gmail.com在留言中写道
news：11 ********************* @ y80g2000hsf.googlegro ups .com ...
"Hapary" <ha****@gmail.comwrote in message
news:11*********************@y80g2000hsf.googlegro ups.com...
> Hello all，
我记得几年前我看过一段代码，它是使用/ * * /和//的组合，以便确定源代码的编译类型。我不记得到底发生了什么，但我认为这就像是如果源代码是由ac编译器编译的，变量的值变为1并且如果
它是用c ++编译器编译的，值变为0.你知道我怎么能找到它吗？
>Hello all,
I remember that I saw a piece of code a few years ago, it was using a
combination of both /* */ and // such that you could determine the
compile type of the source code. I don''t remember exactly what was
happening, but I assume it was something like if the source code was
being compiled by a c compiler the value of a variable became 1 and if
it was compiled with c++ compiler the value became 0. Do you know how
can I find that ?
/ * * /是一个合法的C ++评论，而/ /不是
C中的合法序列.C ++注释互相评论。我无法想到一个方法来实现这个目标。
标准的，可接受的方式是使用#ifdef __cplusplus
构造为此目的提供。
/* */ is a legal C++ comment whilst // is not a legal sequence in
C. C++ comments comment each other out. I can''t think of a way to
achieve this.
The standard, acceptable way is to use the #ifdef __cplusplus
construct provided for the purpose.
//在C99中引入评论。
在C90中，//可以是一个除法运算符，紧接着是
/ * * * /评论的第一个字符。
例如：
#include < stdio.h>
int main（无效）
{
char * messages [] = {
" //不接受评论，
" //评论被接受"
};
int i = 2 / / ** / 2
- 1;
puts（messages [i]）;
返回0;
}
-
Keith Thompson（The_Other_Keith） ks *** @ mib.org < http://www.ghoti.net/~kst>
圣地亚哥超级计算机中心< *< http://users.sdsc.edu/ ~kst>
我们必须做点什么。这是事情。因此，我们必须这样做。
- Antony Jay和Jonathan Lynn，是部长
// introduces a comment in C99.
In C90, // could be a division operator immediately followed by the
first character of a /* ... */ comment.
For example:
#include <stdio.h>
int main(void)
{
char *messages[] = {
"// comments are not accepted",
"// comments are accepted"
};
int i = 2 //**/ 2
- 1;
puts(messages[i]);
return 0;
}
--
Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <* <http://users.sdsc.edu/~kst>
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister"
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