会话变量问题 [英] Session variable problem
问题描述
嗨
我在本网站页面之间传播会话变量时遇到问题
： http://www.meettheancestors.com/sessiontest/index.php
如果您输入任何用户ID和密码并单击登录（不执行实际的
验证），然后移动其他页面和/或
keep刷新页面它最终会显示一些不正确的信息，即当你不是，或者反之亦然时说你登录。
完全相同的代码在这里 http://ccgi.gnosis.free-online.co.uk/index .php
工作得很好意味着第一次PHP安装有问题。
这是3个文件的代码：
=========== index.php =============
<？php
session_start（） ;
if（isset（$ _ POST [''userid'']）&& isset（$ _ POST [''password'']））{
//如果用户刚尝试登录
$ userid = $ _POST [''userid ''];
$密码= $ _POST [''密码''];
//假设有效登录所以设置会话var
$ _SESSION [''loggedinusername''] = $ userid;
}
？>
< html>
< body>
< h1>主页< / h1>
< ;?
if（isset（$ _ SESSION） [''loggedinusername'']））{
echo''您已登录为：''。$ _ SESSION [''loggedinusername'']。''< br /
>'';
echo''< a href =" logout.php">退出< / a>< br />'';
} else {
if（isset（$ userid））{
//如果他们尝试过但未能登录
echo''无法登录。< br />'';
}其他{
//他们还没有尝试登录还是已经退出
echo''你还没有登录。< br />'';
}
//提供登录表格
echo''< form method =" post" action =" index.php">'';
echo''< table>'';
echo''< tr>< td> Userid：< / td>'';
echo''< td>< input type =" text" name =" userid">< / td>< / tr>'';
echo''< tr>< td>密码：< / td>'';
echo''< td>< input type =" password" name =" password">< / td>< / tr>'';
echo''< tr>< td colspan =" 2" align =" center">'';
echo''< input type =" submit" value ="登录">< / td>< / tr>'';
echo''< / table>< / form>'';
}
？>
< br />
< a href =" members_only.php"> ;会员部分< / a>
< / body>
< / html>
===== ====== members_only.php =============
<？php
session_start（）;
echo''< h1>仅限会员< / h1>'';
//检查会话变量
if（isset（$ _ SESSION ['' loggedinusername'']））{
echo''< p>您以''。$ _ SESSION [''loggedinusername'']登录。''< /
p>'';
echo''< p>会员只有内容到这里< / p>'';
}其他{
echo''< p>您尚未登录。< / p>'';
echo''< p>只有登录的会员可能会看到此页。< ; / p>'';
}
e cho''< a href =" index.php">返回主页< / a>'';
？>
=========== logout.php =============
<？php
session_start（） ;
//存储以测试*是否*登录
$ old_user = $ _SESSION [''loggedinusername''];
unset（$ _ SESSION [''loggedinusername'']）;
session_destroy（）;
？>
< html>
< body>
< h1>退出< / h1>
<？php
if（ ！empty（$ old_user））{
echo''已注销。< br />'';
} else {
//如果他们没有登录但是以某种方式来到这个页面
echo''你没有登录，所以还没有登出。< br /
< blockquote class =post_quotes>
>'';
}
？>
< a href =" index.php">返回到主页< / a>
< / body>
< / html>
========= ===============================
我做错了什么或是
在 http的PHP服务器上出现问题或配置问题：//www.meettheancestors.com/phpinfo.php （我的
无法控制）。
任何帮助非常感谢。
Jonathan Attree
_POST [''userid'']）& &安培; isset（
_POST [''password'']））{
//如果用户刚刚尝试登录
userid =
Hi
I am having a problem with session vars being propagated between pages
on this site:
http://www.meettheancestors.com/sessiontest/index.php
If you enter any user id and password and click Log In (no actual
validation is performed), and then move around the other pages and/or
keep refreshing the pages it will eventually display something that is
incorrect i.e. saying your logged in when you aren''t or vice versa.
The exact same code here http://ccgi.gnosis.free-online.co.uk/index.php
works fine implying a problem with the first PHP installation.
Here is the code for the 3 files:
=========== index.php =============
<?php
session_start();
if (isset($_POST[''userid'']) && isset($_POST[''password''])) {
// if the user has just tried to log in
$userid = $_POST[''userid''];
$password = $_POST[''password''];
//assume valid login so set session var
$_SESSION[''loggedinusername''] = $userid;
}
?>
<html>
<body>
<h1>Home page</h1>
<?
if (isset($_SESSION[''loggedinusername''])) {
echo ''You are logged in as: ''.$_SESSION[''loggedinusername''].'' <br /
>'';
echo ''<a href="logout.php">Log out</a><br />'';
} else {
if (isset($userid)) {
// if they''ve tried and failed to log in
echo ''Could not log you in.<br />'';
} else {
// they have not tried to log in yet or have logged out
echo ''You are not logged in.<br />'';
}
// provide form to log in
echo ''<form method="post" action="index.php">'';
echo ''<table>'';
echo ''<tr><td>Userid:</td>'';
echo ''<td><input type="text" name="userid"></td></tr>'';
echo ''<tr><td>Password:</td>'';
echo ''<td><input type="password" name="password"></td></tr>'';
echo ''<tr><td colspan="2" align="center">'';
echo ''<input type="submit" value="Log in"></td></tr>'';
echo ''</table></form>'';
}
?>
<br />
<a href="members_only.php">Members section</a>
</body>
</html>
=========== members_only.php =============
<?php
session_start();
echo ''<h1>Members only</h1>'';
// check session variable
if (isset($_SESSION[''loggedinusername''])) {
echo ''<p>You are logged in as ''.$_SESSION[''loggedinusername''].''</
p>'';
echo ''<p>Members only content goes here</p>'';
} else {
echo ''<p>You are not logged in.</p>'';
echo ''<p>Only logged in members may see this page.</p>'';
}
echo ''<a href="index.php">Back to main page</a>'';
?>
=========== logout.php =============
<?php
session_start();
// store to test if they *were* logged in
$old_user = $_SESSION[''loggedinusername''];
unset($_SESSION[''loggedinusername'']);
session_destroy();
?>
<html>
<body>
<h1>Log out</h1>
<?php
if (!empty($old_user)) {
echo ''Logged out.<br />'';
} else {
// if they weren''t logged in but came to this page somehow
echo ''You were not logged in, and so have not been logged out.<br /
>'';
}
?>
<a href="index.php">Back to main page</a>
</body>
</html>
========================================
Am I doing something wrong or is there a problem or config issue with
the PHP server at http://www.meettheancestors.com/phpinfo.php (which I
have no control over).
Any help greatly appreciated.
Jonathan Attree
_POST[''userid'']) && isset(
_POST[''password''])) {
// if the user has just tried to log in
userid =
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