八进制错误 [英] octal error
问题描述
我一直试图将0到9之间的数字用0领先。对于
示例00或07.我正在使用开关盒。
开关（int）
{
case 01：break;
case 02：break; .....
我的问题出现在08和09，因为它们不是八进制的。是否有任何方法将输入变量强制转换为十进制，尽管它有一个
前导零。
notahipee写道：
我一直在试图从0到9中的一个数字，前导为0.对于
例如00或07.我使用的是开关盒。
您使用的是开关盒吗？
switch（int）
^^^^^^^^^^^
这是语法错误的陈述。
{
case 01：break;
case 02：break; .....
我的问题出现在08和09因为他们不是八进制。
会有什么问题？
有没有
任何方式将输入变量强制转换为十进制，尽管它具有
前导零。
这是你似乎遇到的一个实际问题的一线......但是
我没有看到所谓的行为以下程序。
#include< iostream>
#include< ostream>
int main（）
{
int a = 666;
std :: cin> a;
std :: cout<< ; 你进入了 << a<< std :: endl;
}
如果我输入08，则打印''你输入8''。有什么问题？
V
-
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我想做的事情看起来像这个：
#include< iostream>
#include< ostream>
int main（）
{
int a;
cout<< 输入一个数字 <<结束;
cin> a;
开关（a）
{
案例00：cout< <零;
案例01：cout<<零一个;
等
}
由于前导零将数字更改为八进制，因此它在08处崩溃并且
09.
notahipee写道：
我一直想尝试从0到9的数字前导为0.对于
示例00或07.我使用的是开关盒。
switch（int）
{
案例01：休息;
案例02：休息; .....
我的问题出现在08和09因为它们不是八进制。有没有
任何方法将输入变量强制转换为十进制，尽管它有一个
前导零。
请发布完整的，最少的代码来证明问题。
Brian
I have been trying to cin an number from 0 to 9 with a leading 0. For
example 00 or 07. I was using a switch case.
switch (int)
{
case 01: break;
case 02: break;.....
My problem arises at 08 and 09 because they are not octal. Is there
any way to coerce the input variable to decimal despite it having a
leading zero .
notahipee wrote:I have been trying to cin an number from 0 to 9 with a leading 0. For
example 00 or 07. I was using a switch case.You were using a switch case for what?
switch (int)^^^^^^^^^^^
That''s a syntactically incorrect statement.
{
case 01: break;
case 02: break;.....
My problem arises at 08 and 09 because they are not octal.What problem would that be?
Is there
any way to coerce the input variable to decimal despite it having a
leading zero .This is a glimmer of an actual problem you seem to be having... But
I am not seeing the alleged behaviour in the following program.
#include <iostream>
#include <ostream>
int main()
{
int a = 666;
std::cin >a;
std::cout << "you entered " << a << std::endl;
}
If I enter 08, it prints ''you entered 8''. What''s the problem?
V
--
Please remove capital ''A''s when replying by e-mail
I do not respond to top-posted replies, please don''t ask
What I was trying to do looks like this:
#include <iostream>
#include <ostream>
int main()
{
int a;
cout << "enter a number " << endl;
cin >a;
switch (a)
{
case 00: cout << zero;
case 01: cout << zero one;
etc.
}
Since a leading zero changes the number to octal it crashes at 08 and
09.
notahipee wrote:
I have been trying to cin an number from 0 to 9 with a leading 0. For
example 00 or 07. I was using a switch case.
switch (int)
{
case 01: break;
case 02: break;.....
My problem arises at 08 and 09 because they are not octal. Is there
any way to coerce the input variable to decimal despite it having a
leading zero .Please post complete, minimal code that demonstrates the problem.
Brian
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