C和C ++中的sizeof（'x'） [英] sizeof('x') in C and in C++
问题描述
大家好，
我正在阅读C ++常见问题解答，我惊讶地发现sizeof（''x''）是
等于C ++中的sizeof（char），但是等于C中的sizeof（int）。
1.为什么这样？
2.你能提供一个吗？简单的代码片段可以显示其含义
sizeof（''''）等于sizeof（int）（我希望它是
sizeof（char ）如在C ++中）？
3.如果用C ++代码编译C应用程序，代码是否会中断？
TIA
jimjim写道：大家好，
我正在阅读C ++常见问题解答我很惊讶地发现sizeof（''''）在C ++中等于sizeof（char），但在C中等于sizeof（int）。
1。为什么是这样？
Becasue字符文字是C中的整数类型和字符类型
C ++。
2.你能提供一个简单的代码片段，可以显示sizeof（''''）等于sizeof（int）的含义（我希望它是像C ++中的sizeof（char））？
不，我现在不能。但是你可以通过打印两者的值来实现。
3.如果使用C ++代码编译C应用程序，代码是否会中断？
C和C ++是两种不同的语言。尽量不要混淆这些
两个。
TIA
jimjim写道：大家好，
我正在阅读C ++ FAQ，我惊讶地发现sizeof（''x''）是
等于C ++中的sizeof（char），但是等于C中的sizeof（int）。
1.这是为什么？
" ;由于历史原因
劳伦斯柯比在最近的帖子中对这段历史有所了解
这个小组名为：
为什么一个字符常量大于charcter变量的大小
< vague-memory>
我还记得读一些地方（或者在clc或csc）
BCPL也可能参与其中。
< vague-memory>
< snip>
大家好，
我正在阅读C ++ FAQ，我惊讶地发现sizeof（''x''）是
等于C ++中的sizeof（char），但是等于C中的sizeof（int）。
1.为什么会这样？
2.你能提供一个可以显示的简单代码片段吗？ sizeof（''''）的含义等于sizeof（int）（我希望它是
sizeof（char），就像在C ++中一样）？
3。如果C应用程序是用C ++代码编译的，代码是否中断？
TIA
由于历史原因
搜索为什么字符常量大于字符大小
变量在这一组中（Lawrence Kirby对历史有所了解）
<模糊记忆>
我也依稀记得在某处读书（或者在clc或csc）
BCPL也可能参与其中。
< vague-memory>
< snip>
Hello all,
I was reading the C++ FAQ and I was astonished to learn that sizeof(''x'') is
equal to sizeof(char) in C++, but is equal to sizeof(int) in C.
1. Why is this?
2. Can you provide a simple code fragment that can exibit the implications
of sizeof(''x'') being equal to sizeof(int) (I would expect it to be
sizeof(char) as in C++)?
3. Will the code break if a C application is compiled with C++ code?
TIA
jimjim wrote:Hello all,
I was reading the C++ FAQ and I was astonished to learn that sizeof(''x'') is
equal to sizeof(char) in C++, but is equal to sizeof(int) in C.
1. Why is this?
Becasue character literal is of integer type in C and character type in
C++.
2. Can you provide a simple code fragment that can exibit the implications
of sizeof(''x'') being equal to sizeof(int) (I would expect it to be
sizeof(char) as in C++)?
No, I can''t right now. But you can, by printing the value of both.
3. Will the code break if a C application is compiled with C++ code?
C and C++ are two different language. Try to refrain from mixing these
two.
TIA
jimjim wrote:Hello all,
I was reading the C++ FAQ and I was astonished to learn that sizeof(''x'') is
equal to sizeof(char) in C++, but is equal to sizeof(int) in C.
1. Why is this?
"For historical reasons"
Lawrence Kirby shed''s some light on that history in the recent thread in
this group titled:
"Why is a character constant more than size of charcter variable"
<vague-memory >
I also vageuly remember reading some where (either in clc or in csc)
that BCPL also might have had an hand in that.
<vague-memory>
<snip>
jimjim wrote:Hello all,
I was reading the C++ FAQ and I was astonished to learn that sizeof(''x'') is
equal to sizeof(char) in C++, but is equal to sizeof(int) in C.
1. Why is this?
2. Can you provide a simple code fragment that can exibit the implications
of sizeof(''x'') being equal to sizeof(int) (I would expect it to be
sizeof(char) as in C++)?
3. Will the code break if a C application is compiled with C++ code?
TIA
"For historical reasons"
search for "Why is a character constant more than size of character
variable" in this group (Lawrence Kirby sheds some light on the history)
<vague-memory >
I also vaguely remember reading some where (either in clc or in csc)
that BCPL also might have had an hand in that.
<vague-memory>
<snip>
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