宏可以这样做吗？ [英] Can A Macro Do This?
问题描述
嗨
现在我做多个断言来验证多个值：
断言（foo == X）;
断言（foo == Y）;
断言（foo == Z）;
有没有办法宏观化这个并在一个电话？
MYASRT（foo，（X || Y || Z））;
...或者......
MYASRT（foo，OR，X，Y，Z））;
TIA，
-T
Hi
Right now I do multiple asserts to verify multiple values:
assert(foo==X);
assert(foo==Y);
assert(foo==Z);
Is there any way to macro-ize this and do it in one call?
MYASRT(foo, (X||Y||Z));
... or maybe...
MYASRT(foo,OR,X,Y,Z));
TIA,
-T
推荐答案
gamename写道：
gamename wrote:
嗨
现在我做多个断言来验证多个值：
断言（foo == X）;
断言（foo == Y）;
断言（foo == Z）;
有没有办法宏观化这个并在一次通话中完成？
MYASRT（foo，（X || Y || Z）） ;
...或者......
MYASRT（foo，OR，X，Y，Z））;
Hi
Right now I do multiple asserts to verify multiple values:
assert(foo==X);
assert(foo==Y);
assert(foo==Z);
Is there any way to macro-ize this and do it in one call?
MYASRT(foo, (X||Y||Z));
... or maybe...
MYASRT(foo,OR,X,Y,Z));
出了什么问题：
断言（foo == X || foo == Y || foo == Z）;
What''s wrong with:
assert(foo == X || foo == Y || foo == Z);
santosh写道：
santosh wrote:
gamename写道：
gamename wrote:
>嗨
现在我做多个断言来验证多个值：
断言（foo == X）;
断言（foo = = Y）;
断言（foo == Z）;
有没有办法宏观化这个并在一次通话中完成？
MYASRT（foo，（X || Y || Z））;
......或者......
MYASRT（foo，OR，X，Y，Z））;
>Hi
Right now I do multiple asserts to verify multiple values:
assert(foo==X);
assert(foo==Y);
assert(foo==Z);
Is there any way to macro-ize this and do it in one call?
MYASRT(foo, (X||Y||Z));
... or maybe...
MYASRT(foo,OR,X,Y,Z));
出了什么问题：
断言（foo == X || foo == Y || foo == Z）;
What''s wrong with:
assert(foo == X || foo == Y || foo == Z);
这是错误的！
应该是：
断言（ foo == X&& foo == Y&& foo == Z）;
-
jacob navia
jacob at jacob point remcomp point fr
logiciels / informatique
http://www.cs.virginia.edu/~lcc-win32
jacob navia写道：
jacob navia wrote:
santosh写道：
santosh wrote:
> gamename写道：
>gamename wrote:
>>嗨
现在我做多个断言来验证多个值：
断言（foo == X）;
断言（foo == Y）;
assert（foo == Z）;
有没有办法宏观化这个并在一次调用中完成它？
MYASRT（foo，（X || Y || Z） ））;
......或者可能是...
MYASRT（foo，OR，X，Y，Z））;
>>Hi
Right now I do multiple asserts to verify multiple values:
assert(foo==X);
assert(foo==Y);
assert(foo==Z);
Is there any way to macro-ize this and do it in one call?
MYASRT(foo, (X||Y||Z));
... or maybe...
MYASRT(foo,OR,X,Y,Z));
有什么问题：
断言（foo == X || foo == Y || foo == Z）;
What''s wrong with:
assert(foo == X || foo == Y || foo == Z);
这是错误的！
应该是：
断言（foo == X && foo == Y&& foo == Z）;
That is wrong!
Should be:
assert(foo == X && foo == Y && foo == Z);
否则是。你是对的。
在我的辩护中，我被MYASRT所左右。由
OP呈现的宏，他使用OR运算符而不是AND。
Oops yes. You are right.
In my defence I got sidetracked by the "MYASRT" macro presented by the
OP, where he uses the OR operator, instead of the AND.
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