我的错误在哪里？ [英] Where is my mistake?
问题描述
我是自学C程序的学生。
希望有人可以帮我解决这个问题。
这个程序使用调用函数在用户定义的范围内生成随机数
我使用了调用函数 GenRndNum" ;.范围是2和10.
问题是我获得了2次调用产生的相同的2个随机数。
我应该得到2个不同的随机数。有人可以指出我的错误吗？
谢谢
Khoon。
/ *在用户定义的范围内生成随机数。* /
#include< stdio.h>
#include< stdlib.h>
#include< time.h> ;
int GenRndNum（int x，int y）;
int main（无效）
{
int MinRange;
int MaxRange;
int RndNum1;
int RndNum2;
printf（请输入两个范围的最小值和最大值）;
printf（" \\\
random numbers>" ）;
scanf（"％d％d"，& MinRange，& MaxRange）;
RndNum1 = GenRndNum（MinRange，MaxRange）;
printf（" RndNum1 =％d \ n"，RndNum1）;
RndNum2 = GenRndNum（MinRange，MaxRange）;
printf （RndNum2 =％d \ n，RndNum2）;
返回0;
}
int G. enRndNum（int x，int y）
{int z;
srand（time（NULL））;
printf（ x =％d，y =％d \ n，x，y）;
z = rand（）％（（y + 1） - x）+ x;
printf（" z =％d \ n"，z）;
return（z）;
}
/ * -----------------------
输出结果：
请输入两个
随机数范围的最小值和最大值> 2 10
x = 2，y = 10
z = 5
RndNum1 = 5
x = 2，y = 10
z = 5
RndNum2 = 5
按任意键继续_
* /
I am self study C program student.
Hope someone can help me with this problem.
This program generates random numbers over a user defined range using call function
I used the call function " GenRndNum". The range is 2 and 10.
The problem is that I get the same 2 random numbers generated over 2 calls.
I should get 2 different random numbers. Can someone please point out my mistake?
Thanks
Khoon.
/* Generation of Random Numbers over a User Defined Range.*/
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int GenRndNum (int x, int y);
int main (void)
{
int MinRange;
int MaxRange;
int RndNum1;
int RndNum2;
printf ("Please key in the Minimum and Maximum Value for the Range of the two ");
printf ("\nrandom numbers> ");
scanf ( "%d %d", &MinRange, &MaxRange);
RndNum1= GenRndNum (MinRange, MaxRange);
printf ("RndNum1 = %d\n",RndNum1);
RndNum2= GenRndNum (MinRange, MaxRange);
printf ("RndNum2 = %d\n",RndNum2);
return 0;
}
int GenRndNum (int x, int y )
{ int z;
srand (time(NULL));
printf ("x = %d, y = %d\n",x,y);
z = rand() % ((y+1 ) - x ) + x;
printf ("z = %d\n",z);
return (z);
}
/*-----------------------
Result of Output:
Please key in the Minimum and Maximum Value for the Range of the two
random numbers> 2 10
x = 2, y = 10
z = 5
RndNum1 = 5
x = 2, y = 10
z = 5
RndNum2 = 5
Press any key to continue_
*/
推荐答案
Red Dragon写道：
Red Dragon wrote:
我是自学C程序的学生。
希望有人可以帮我解决这个问题。
I am self study C program student.
Hope someone can help me with this problem.
< snip>
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其余的消息被忽略，抱歉。
S.
<snip>
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You''re using Outlook Express. To change the format, choose Tools ->
Options, click on the Send tab, and make sure the radio button "Plain
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Rest of the message ignored, sorry.
S.
Red Dragon写道：
Red Dragon wrote:
[...]
问题是我获得了2次调用产生的相同的2个随机数。
我应该得到2个不同的随机数。有人可以指出我的错误吗？
[...]
int GenRndNum（int x，int y）
{int z;
srand（time（空值））;
这是它。请参阅comp.lang.c
常见问题（FAQ）列表中的问题13.17
http://www.eskimo.com/~scs/C-faq/top.html
事实上，见所有问题13.15到13.20;还有
与你正在做的事情有关的其他一些问题，
FAQ可以帮助你解决它们。
printf（" ; x =％d，y =％d \ n"，x，y）;
z = rand（）％（（y + 1） - x）+ x;
printf（" z =％d \ n"，z）;
return（z）;
}
[...]
The problem is that I get the same 2 random numbers generated over 2 calls.
I should get 2 different random numbers. Can someone please point out my mistake?
[...]
int GenRndNum (int x, int y )
{ int z;
srand (time(NULL));
Here it is. See Question 13.17 in the comp.lang.c
Frequently Asked Questions (FAQ) list at
http://www.eskimo.com/~scs/C-faq/top.html
In fact, see all of Questions 13.15 through 13.20; there
are a few other problems with what you''re doing, and the
FAQ can help you solve them.
printf ("x = %d, y = %d\n",x,y);
z = rand() % ((y+1 ) - x ) + x;
printf ("z = %d\n",z);
return (z);
}
-
Eric Sosman
es ***** @ acm-dot- org.inva lid
--
Eric Sosman
es*****@acm-dot-org.invalid
你总是使用相同的srand值。试试这个：
long tm;
time（& tm）;
srand（tm）;
you are using always the same srand value. try this:
long tm;
time(&tm);
srand(tm);
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