查找整数问题 [英] Finding the Integers Question
问题描述
您好，
我是C的新手所以请原谅我的无能。
如果给我一个文件" jfewuuj3uefi8jkw128jdmnsdf\ ;;''d1904"
我想将每个0-9整数的出现捕获到数组中。
所以在阵列中我会有{3,8,1,2,8,1,9,0,4}
我该怎么做呢？ SCANF？ fgets？
谢谢:)
Hello,
I''m very new to C so please forgive my ineptitude.
If I am given a file with "jfewuuj3uefi8jkw128jdmnsdf\s;''d1904"
I want to capture each occurence of an integer 0-9 into an array.
So in the array I would have {3,8,1,2,8,1,9,0,4}
How would I go about doing this? scanf? fgets?
Thank you :)
推荐答案
jobo写道：
jobo wrote:
你好，
我是C的新手所以请原谅我的无能。
如果给我一个带有jfewuuj3uefi8jkw128jdmnsdf \ s;''d1904"
的文件，我想将每个0-9整数的出现捕获到一个数组中。
所以在数组中我会有{3,8,1,2,8,1,9,0,4}
怎么样？我这样做了吗？ SCANF？与fgets？
Hello,
I''m very new to C so please forgive my ineptitude.
If I am given a file with "jfewuuj3uefi8jkw128jdmnsdf\s;''d1904"
I want to capture each occurence of an integer 0-9 into an array.
So in the array I would have {3,8,1,2,8,1,9,0,4}
How would I go about doing this? scanf? fgets?
看看fgetc和isdigit。
-
Thomas M. Sommers - tm*@nj.net - AB2SB
Take a look at fgetc and isdigit.
--
Thomas M. Sommers -- tm*@nj.net -- AB2SB
这里我的代码就是：
arr [i] = fgetc（"％d"）;
我正在接受a从不兼容的指针传递''fgetc''的参数1
type"错误。
T.M. Sommers写道：
Here''s what I have in my code:
arr[i] = fgetc("%d ");
I''m gettting a "passing argument 1 of ''fgetc'' from incompatible pointer
type" error.
T.M. Sommers wrote:
jobo写道：
jobo wrote:
你好，
我是C的新手所以请原谅我的无能。
如果给我一个文件jfewuuj3uefi8jkw128jdmnsdf \ s;''d1904"
我想将每个0-9整数的出现捕获到一个数组中。
所以在数组中我会得到{3,8,1， 2,8,1,9,0,4}
我该怎么做呢？ SCANF？与fgets？
Hello,
I''m very new to C so please forgive my ineptitude.
If I am given a file with "jfewuuj3uefi8jkw128jdmnsdf\s;''d1904"
I want to capture each occurence of an integer 0-9 into an array.
So in the array I would have {3,8,1,2,8,1,9,0,4}
How would I go about doing this? scanf? fgets?
看看fgetc和isdigit。
-
Thomas M. Sommers - tm*@nj.net - AB2SB
Take a look at fgetc and isdigit.
--
Thomas M. Sommers -- tm*@nj.net -- AB2SB
jobo写道：
jobo wrote:
TM Sommers写道：
T.M. Sommers wrote:
>> jobo写道：
>>jobo wrote:
>>> I'对C来说很新，所以请原谅我的无能。
如果给我一个带有jfewuuj3uefi8jkw128jdmnsdf \;的文件''d1904"
我想抓住每个出现0到整数的整数。
所以在数组中我会有{3,8,1,2,8,1,9,0,4}
我该怎么做呢？ SCANF？与fgets？
>>>I''m very new to C so please forgive my ineptitude.
If I am given a file with "jfewuuj3uefi8jkw128jdmnsdf\s;''d1904"
I want to capture each occurence of an integer 0-9 into an array.
So in the array I would have {3,8,1,2,8,1,9,0,4}
How would I go about doing this? scanf? fgets?
看看fgetc和isdigit。
Take a look at fgetc and isdigit.
这是我在代码中的内容：
arr [i] = fgetc（"％d"）;
我从不兼容的指针中获取fgetc的传递参数1
type"错误。
Here''s what I have in my code:
arr[i] = fgetc("%d ");
I''m gettting a "passing argument 1 of ''fgetc'' from incompatible pointer
type" error.
阅读fgetc的手册页。它需要一个FILE *作为参数，
并返回一个int。你想要这样的东西：
int ch;
while（（ch = fgetc（file_pointer））！= EOF）{
if（isdigit（ch））{
/ *你的数组中的东西ch * /
}
}
假设file_pointer是一个FILE *并且已经成功打开了用于阅读的
，并且相应的头文件已经是
#included。
-
Thomas M. Sommers - tm*@nj.net - AB2SB
Read the man page for fgetc. It takes a FILE * as an argument,
and returns an int. You want something like this:
int ch;
while ( (ch = fgetc(file_pointer)) != EOF ) {
if ( isdigit(ch) ) {
/* stuff ch in your array */
}
}
Assuming file_pointer is a FILE * and has been successfully
opened for reading, and the appropriate header files have been
#included.
--
Thomas M. Sommers -- tm*@nj.net -- AB2SB
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