无效功能中的两个出口点？ [英] two exiting points in void function?

问题描述

有没有办法在void函数中退出点？我不想要

退出程序但只是这个功能。


任何答案都赞赏。


L. Westmeier

Is there a way to have to exiting point in a void function? I don''t want
to exit the program but just this function.

Any answers appreciated.

L. Westmeier

推荐答案

在文章< bo ********** @ hahn.informatik.hu -berlin.de>，L。Westmeier写道：

In article <bo**********@hahn.informatik.hu-berlin.de>, L. Westmeier wrote:

有没有办法在void函数中退出点？我不想退出程序而只是退出程序。

任何答案都赞赏。

Is there a way to have to exiting point in a void function? I don''t want
to exit the program but just this function.

Any answers appreciated.

#include< stdio.h> ;


void foo（int e）

{

if（e == 0）{

返回;

}


printf（没有提前退出，e ==％d \ n，e）; < br $> b $ b}

-

Andreas K？h？ri

#include <stdio.h>

void foo(int e)
{
if (e == 0) {
return;
}

printf("didn''t exit early, e == %d\n", e);
}
--
Andreas K?h?ri

L. Westmeier写道：

L. Westmeier wrote:

有没有办法在void函数中退出点？我不想退出程序而只是退出程序。

Is there a way to have to exiting point in a void function? I don''t want
to exit the program but just this function.

使用return;

Use return;

Grumble写道：

Grumble wrote:

L. Westmeier写道：

L. Westmeier wrote:

有没有办法在void函数中退出点？我不想退出程序而只是退出程序。

Is there a way to have to exiting point in a void function? I don''t
want to exit the program but just this function.

使用return;

Use return;

感谢快速回复:-)

thanks for the fast reply :-)

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