不占用空间的std :: vector的别名 [英] Alias for a std::vector that does not take space

问题描述

我得到了std :: vector工作的前一个别名，发现它占用了指针的

空间。我想找到一种方法来为std :: vector做一个别名，

不会占用任何空间。有没有办法做到这一点？ （我试过#define Name1

Name2并且它没有编译）

I got the previous alias to std::vector working, and found that it takes up the
space of a pointer. I want to find a way to do an alias to a std::vector that
does not take up any space. Is there any way to do this? (I tried #define Name1
Name2 and it didn''t compile)

推荐答案

Peter Olcott写道：

Peter Olcott wrote:

我得到了std :: vector工作的前一个别名，发现它占用了

空间一个指针。我想找到一种方法来为std :: vector做一个别名，

不会占用任何空间。有没有办法做到这一点？ （我试过#define Name1

Name2并且它没有编译）

I got the previous alias to std::vector working, and found that it takes up the
space of a pointer. I want to find a way to do an alias to a std::vector that
does not take up any space. Is there any way to do this? (I tried #define Name1
Name2 and it didn''t compile)

否则没有。也许你应该尝试解释你的问题

而不是。


/ Peter

No there is not. Perhaps you should try to explain your problem
instead.

/Peter

Peter Olcott写道：

Peter Olcott wrote:

我得到了std :: vector工作的前一个别名，发现它占用了

的空间一个指针。我想找到一种方法来为std :: vector做一个别名，

不会占用任何空间。有没有办法做到这一点？ （我尝试了#define Name1

Name2并且它没有编译）

I got the previous alias to std::vector working, and found that it takes up the
space of a pointer. I want to find a way to do an alias to a std::vector that
does not take up any space. Is there any way to do this? (I tried #define Name1
Name2 and it didn''t compile)

#define应该有效。 ..但它是一把生硬的锤子：

#define Fred George


struct S {

vector< intGeorge; < br $>
};


s s;


s.Fred.push_back（2）;

The #define should have worked... but it''s a blunt hammer:
#define Fred George

struct S {
vector<intGeorge;
} ;

S s;

s.Fred.push_back(2);

Peter Olcott写道：

Peter Olcott wrote:

我得到了std :: vector工作的前一个别名，并发现它占用了指针的

空间。我想找到一种方法来为std :: vector做一个别名，

不会占用任何空间。有没有办法做到这一点？

I got the previous alias to std::vector working, and found that it takes up the
space of a pointer. I want to find a way to do an alias to a std::vector that
does not take up any space. Is there any way to do this?

是：使用方法。例如，


struct {

std :: vector< intm_vec;

std :: vector< int>& alias（）{return m_vec; }

std :: vector< intconst& alias（）const {return m_vec; }

};


HTH，

Michiel Salters

Yes: use a method. E.g.

struct {
std::vector<intm_vec;
std::vector<int>& alias() { return m_vec; }
std::vector<intconst& alias() const { return m_vec; }
};

HTH,
Michiel Salters

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