重载运算符 [英] Overloading Operators

问题描述

我正在完成一项学校作业，所以请不要告诉我

解决方案。我只是想要一些方向。


我应该重载>，<，==，！=，> =和< =运算符使用

bool。我在看到需要发生的事情时遇到了一些问题

。我只是不确定我是怎么做到的。重载函数

是否会识别<通常<？我做了一个

IF（a.letters< b.letters）{

返回true

}

其他{

返回false

}


??这是我需要的逻辑吗？


KL

I am working on a school assignment, so please don''t tell me the
solution. I just want some direction.

I am supposed to overload the >, <, ==, !=, >=, and <= operators using
bool. I am having a bit of a problem in seeing what needs to happen
here. I am just not sure how I do this. Will the overloading function
recognize a < and a usual <? Do I do an
IF (a.letters < b.letters){
return true
}
else {
return false
}

?? Is that the logic I need?

KL

推荐答案

KL写道：

KL wrote:

我正在完成一项学校作业，所以请不要告诉我
解决方案。我只是想要一些方向。


你不经常在这里发帖，对吧？ ;-)

我应该使用
bool重载>，<，==，！=，> =和< =运算符。我在看到需要发生的事情时遇到了一些问题。


嗯，这取决于。

我不知道我是怎么做到的。重载功能是否会识别<通常<？


不确定你的意思。你的操作员只是一个功能，你可以在其中使用

所有可用于任何其他功能的东西。

我做一个
IF（a .letters< b.letters）{
返回true
}
其他{
返回false
}

??这是我需要的逻辑吗？

I am working on a school assignment, so please don''t tell me the
solution. I just want some direction.
You are not posting here very often, right? ;-)
I am supposed to overload the >, <, ==, !=, >=, and <= operators using
bool. I am having a bit of a problem in seeing what needs to happen
here.
Well, that depends.
I am just not sure how I do this. Will the overloading function
recognize a < and a usual <?
Not sure what you mean. Your operator is just a function, and you can use
everything in it that you can use in any other function.
Do I do an
IF (a.letters < b.letters){
return true
}
else {
return false
}

?? Is that the logic I need?

是的，基本上。但是，你可以省略if而只是写：


返回a.letters< b.letters;


，因为'a.letters< b.letters''只是一个真正的布尔值

或false，具体取决于值。

Yes, basically. However, you can leave out the if and just write:

return a.letters < b.letters;

since the result of ''a.letters < b.letters'' is just a boolean that is true
or false, depending on the values.

Rolf Magnus写道：

Rolf Magnus wrote:

KL写道：

KL wrote:

我正在完成一项学校作业，所以请不要告诉我
解决方案。我只是想要一些方向。

I am working on a school assignment, so please don''t tell me the
solution. I just want some direction.

你不经常在这里发帖，对吧？ ; - ）

You are not posting here very often, right? ;-)

这是对的。我只是在遇到困难时张贴。所以基本上，不是经常。

That is right. I just post when I get stuck. So basically, not very often.

我应该重载>，<，==，！=，> =和< =运营商
使用bool。在看到这里发生什么需要时，我遇到了一些问题。

I am supposed to overload the >, <, ==, !=, >=, and <= operators
using bool. I am having a bit of a problem in seeing what needs to
happen here.

嗯，这取决于。

Well, that depends.

I我只是不确定我是怎么做到的。重载功能是否会识别<和通常的<？

I am just not sure how I do this. Will the overloading function
recognize a < and a usual <?

不确定你的意思。您的操作员只是一个功能，您可以使用其中可以用于任何其他功能的所有内容。

Not sure what you mean. Your operator is just a function, and you can
use everything in it that you can use in any other function.

我做一个
IF（a .letters< b.letters）{
返回true
}
其他{
返回false
}

??这是我需要的逻辑吗？

Do I do an
IF (a.letters < b.letters){
return true
}
else {
return false
}

?? Is that the logic I need?

是的，基本上。但是，你可以省略if而只是写：

返回a.letters< b.letters;

因为'a.letters< b.letters''只是一个布尔值，它是真或假的，取决于值。

Yes, basically. However, you can leave out the if and just write:

return a.letters < b.letters;

since the result of ''a.letters < b.letters'' is just a boolean that is
true or false, depending on the values.

好​​的，所以当它被调用时，例如a< b，我的参数（已经给出了

）只传递了b。所以我的问题是如何引用一个部分。

它可以被称为任何东西。如何在我的超载

函数中引用它？


对不起，如果这看起来像一个基本问题，但就在我认为我有那个

想通了，它再次跳出我的脑袋。


-


KL

你的论点是合理的，只有声音。 -Benjamin Franklin


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OK, so when it is called, for example a<b, my parameters (which were already
given) only passes the b. So my question is how to reference the a part.
It could be called anything. How do I reference it in my overloading
function?

Sorry if this seems like a basic question, but just when I think I have that
figured out, it jumps out of my head again.

--

KL

Your argument is sound, nothing but sound. -Benjamin Franklin

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调用类似（a< b）的语句，它扩展为以下内容：

a.operator<（b）;即，运营商<调用对象传递对象b

作为参数。因此你不必担心对象a（

提供a和b是相同类型/类/结构/联合的对象）。

也是你在重载的

函数中只有一个参数的原因。

when an statement like (a < b) is invoked, it expands to the following:
a.operator<(b); ie, operator < is invoked for object a passing object b
as the parameter. hence you don''t have to worry about object a (
provided a and b are objects of the same type/class/struct/union).that
is also the reason you have only one parameter in the overloaded
function.

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