x = x * x vs. i = i ++ [英] x=x*x vs. i=i++
问题描述
为什么i = i ++ undefined而x = x * x没关系？
why is i=i++ undefined while x=x*x is alright?
推荐答案
al.c ... @ gmail.com skrev：
al.c...@gmail.com skrev:
为什么i = i ++ undefined而x = x * x好吗？
why is i=i++ undefined while x=x*x is alright?
因为i = i ++包含对i的赋值。 x = x * x只包含一个
赋值给x。
当同一个变量有两个赋值而没有干预
sequenceproblem时，你遇到了麻烦。
彼得
Because i=i++ contains to assignments to i. x=x*x only contains one
assignment to x.
It is when the same variable has two assignments without an intervening
sequenceproblem, you get into troubles.
Peter
peter koch写道：
peter koch wrote:
al .c ... @ gmail.com skrev：
al.c...@gmail.com skrev:
为什么i = i ++ undefined而x = x * x好吗？
why is i=i++ undefined while x=x*x is alright?
因为i = i ++包含对i的赋值。 x = x * x只包含一个对x的赋值。
当同一个变量有两个赋值而没有介入的序列问题时，你会遇到麻烦。
彼得
出于好奇，i = ++ i怎么样？在这种情况下，至少看起来两个作业都做同样的事情。
Out of curiousity, what about i = ++i? In this case it at least seems
that both assignments do the same thing.
On 2006-03-21 21:04:16 - 0500，Mark P
< us **** @ fall2005REMOVE.fastmailCAPS.fm>说：
On 2006-03-21 21:04:16 -0500, Mark P
<us****@fall2005REMOVE.fastmailCAPS.fm> said:
peter koch写道：
peter koch wrote:
al.c ... @ gmail.com skrev：
al.c...@gmail.com skrev:
为什么i = i ++ undefined而x = x * x没关系？
why is i=i++ undefined while x=x*x is alright?
因为i = i ++包含对i的赋值。 x = x * x只包含一个对x的赋值。
当同一个变量有两个赋值而没有介入的序列问题时，你会遇到麻烦。
彼得
出于好奇，i = ++ i怎么样？在这种情况下，它至少看起来两个作业都做同样的事情。
Out of curiousity, what about i = ++i? In this case it at least seems
that both assignments do the same thing.
如果他们做同样的事情并不重要。 。事实上，其中两个是
，这两个行为都是未定义的行为。
-
Clark S. Cox，III
< a href =mailto：cl ******* @ gmail.com> cl ******* @ gmail.com
It doesn''t matter if they "do the same thing". The fact that there are
two of them makes it undefined behavior.
--
Clark S. Cox, III
cl*******@gmail.com
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