删除删除！ [英] delete on delete !

问题描述

如果我在之前删除的对象上再删除一次，那么

怎么回事

系统应该表现如何？


这是一种不可预测的行为吗？


谢谢

Sandeep

推荐答案

Sandeep Grover写道：

Sandeep Grover wrote:

如果我再做一次删除一个早先被删除的对象，然后
系统应该如何表现？

这是一种不可预测的行为吗？

Hi,

If I do another delete on an object which has been deleted earlier, then
how is
the system expected to behave ?

Is it an unpredictable behavior ??

是的，不可预测的。


有些人会窒息，有些是破坏者SEGV，它会继续下去。

Yes, unpredictable.

Some will choke, some destructors SEGV, it goes on and on.

Sandeep Grover写道：

Sandeep Grover wrote:

如果我对之前删除的对象进行另一次删除，那么
系统应该如何表现？

这是一种不可预测的行为吗？

If I do another delete on an object which has been deleted earlier, then
how is the system expected to behave?

Is it an unpredictable behavior ??

它是精炼，所以在理论上，是的;任何事情都可能发生。


S

It''s undefined, so in theory, yes; anything could happen.

S

Sandeep Grover写道：

Sandeep Grover wrote:

如果我对之前删除的对象进行另一次删除，那么
系统应该如何表现？

是这是一种不可预测的行为？

If I do another delete on an object which has been deleted earlier, then
how is the system expected to behave?

Is it an unpredictable behavior ??

它是未定义的，所以从理论上讲，是的;什么都可能发生。

S

It''s undefined, so in theory, yes; anything could happen.

S

谢谢！


所以，如果我有一个数组指针;不止一个条目可以指向

到/ b $ b相同的内存块（使用new分配）。我如何确保$

最终只删除该条目一次。我不想在构造函数中使用引用计数

的东西。

Thanks !

So, if I have an array of pointers; more than one of the entries could point
to
the same chunk of memory (allocated using new). How do I ensure that I
end up deleting that entry only once. I dont want to use reference-counting
kind of thing in constructor.

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