将char转换为int。 [英] Converting char to int.

问题描述

大家好！


我知道这听起来像个愚蠢的问题，但我需要改变是否

不是一个字母（来自char array）是一个数字。我用atoi试过了

，但对于任何角色来说它似乎都会返回0。这没关系，

除非该字符碰巧是''0'。我确定我在这里错过了一些东西。任何指针都会很棒。

数组中的每个字符都是单独变化的，并且使用所有字符数字构建新的字符串流字符串

。所有字母都是字母（或者

至少''应该是''ommited。


提前谢谢。


Daz

Hi all!

I know this sounds like a stupid question, but I need to varify whether
ot not a single char (from a char array) is a number. I have tried
using atoi, but it seems to return ''0'' for any characters. This is ok,
unless the character happens to be a ''0''. I am certain I am missing
something here. Any pointers would be fantastic. Each character in the
array is varified individually and a new stringstream string is built
using all of chars that are numbers. All chars that are letters are (or
at least ''should be'' ommited.

Thanks in advance.

Daz

推荐答案

Daz写道：

Daz wrote:

大家好！

我知道这听起来像个愚蠢的问题，但是我需要改变是否单个char（来自char数组）是一个数字。

Hi all!

I know this sounds like a stupid question, but I need to varify whether
ot not a single char (from a char array) is a number.

查找函数std :: isdigit（）。就是这样。

Look up the function std::isdigit(). It does exactly that.

Rolf Magnus写道：

Rolf Magnus wrote:

查找函数std :: isdigit（）。它就是这样。

Look up the function std::isdigit(). It does exactly that.

呵呵。巧妙！


谢谢Rolf！:)

Hehe. Ingenious!

Thanks Rolf! :)

Rolf Magnus写道：

Rolf Magnus wrote:

查找函数std :: isdigit（）。它就是这样。

Look up the function std::isdigit(). It does exactly that.

裤子！我甚至无法正确引用文字......


再次感谢Rolf！

Pants! I can''t even quote text properly...

Thanks again Rolf!

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