分发清单 [英] disgrating a list
问题描述
您好，
我如何能够（可能不是一个好词）列出一个列表？对于
例如：
a = [1,2]
b = 3
c = [a ] + [b]＃使得[[1,2]，3]
然后如何将c（[[1,2]，3]）改为[1， 2,3]？我有一个简单的
功能：
========================
def flatten（l）：
r = []
s = [l]
而len（s）0：
i = s.pop（）
if i .__ class__ == list：
for c in i：
s.append（c）
else：
r.append（i）
返回r
= =======================
但是这个函数实际上并没有在python-way中进行。难道不是
python是一个不起眼的功能还是构建它？
Greetz，
Noud Aldenhoven
Hello,
How can I disgrate (probably not a good word for it) a list? For
example:
a = [1,2]
b = 3
c = [a] + [b] # which makes [[1,2],3]
Then how can I change c ([[1,2],3]) into [1,2,3]? I have a simple
function for this:
========================
def flatten(l):
r = []
s = [l]
while len(s) 0:
i = s.pop()
if i.__class__ == list:
for c in i:
s.append(c)
else:
r.append(i)
return r
========================
But this function isn''t really doing it in the "python-way". Doesn''t
have python an obscure function or buildin to do this?
Greetz,
Noud Aldenhoven
推荐答案
jwaixs schrieb：
jwaixs schrieb:
你好，
我如何能够列出一份清单（可能不是一个好词）？对于
例如：
a = [1,2]
b = 3
c = [a ] + [b]＃使[[1,2]，3]
Hello,
How can I disgrate (probably not a good word for it) a list? For
example:
a = [1,2]
b = 3
c = [a] + [b] # which makes [[1,2],3]
为什么要在列表中包装？只需
c = a + [b]
就可以了。
Diez
Why do you wrap a in a list? Just
c = a + [b]
will do it.
Diez
Diez B. Roggisch写道：
Diez B. Roggisch wrote:
为什么要包装一个清单？只需
c = a + [b]
就可以了。
Why do you wrap a in a list? Just
c = a + [b]
will do it.
是的我知道，但问题是我不知道''a'是否是一个清单。我b $ b可以进行类型检查，但我不想以这种方式编程。
Noud
Yes I know, but the problem is I don''t know if ''a'' is a list or not. I
could make a type check, but I don''t want to program in that way.
Noud
jwaixs写道：
jwaixs wrote:
你好，
我怎么能这样做（可能不是一个好词（一个列表）？对于
例如：
a = [1,2]
b = 3
c = [a ] + [b]＃使得[[1,2]，3]
然后如何将c（[[1,2]，3]）改为[1， 2,3]？我有一个简单的
功能：
========================
def flatten（l）：
r = []
s = [l]
而len（s）0：
i = s.pop（）
if i .__ class__ == list：
for c in i：
s.append（c）
else：
r.append（i）
返回r
= =======================
但是这个函数实际上并没有在python-way中进行。难道没有
python是一个不起眼的功能还是构建这样做？
Hello,
How can I disgrate (probably not a good word for it) a list? For
example:
a = [1,2]
b = 3
c = [a] + [b] # which makes [[1,2],3]
Then how can I change c ([[1,2],3]) into [1,2,3]? I have a simple
function for this:
========================
def flatten(l):
r = []
s = [l]
while len(s) 0:
i = s.pop()
if i.__class__ == list:
for c in i:
s.append(c)
else:
r.append(i)
return r
========================
But this function isn''t really doing it in the "python-way". Doesn''t
have python an obscure function or buildin to do this?
不，它不是，但它很容易自己滚动，例如使用
递归生成器;事实上，如果你搜索过flatten在clpy的
google组中，您会发现： http ：//tinyurl.com/ndobk
乔治
No, it doesn''t, but it''s easy to roll one on your own, e.g. using a
recursive generator; in fact, if you had searched for "flatten" in the
google group of c.l.py, you''d find this: http://tinyurl.com/ndobk
George
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