void *等同于char *？ [英] Is a void * equivalent to a char *?
问题描述
给出以下代码：
#include< stdio.h>
int main（无效）
{
char array [100] ="你最喜欢的车是什么？" ;;
void * vp =& array;
printf（"％s \ n"，vp）;
返回0;
}
printf（）语句是否正确？或者是vp所需的char * *
printf（"％s \ n"，（char *）vp）;
也就是说，假设void *指向一个字符串，打印字符串的正确方法是什么？
Given the following code:
#include <stdio.h>
int main(void)
{
char array[100] = "What is your favorite car?";
void *vp = &array;
printf("%s\n", vp);
return 0;
}
Is the printf() statement correct? Or is a cast to char * required for vp?
printf("%s\n", (char *) vp);
That is, assuming a void * is pointing to a string, what is the proper way
to print the string?
推荐答案
在文章< Xn ************************ @ 207.217.125.201>，
planetzoom < fo*@fox.orgwrote：
In article <Xn************************@207.217.125.201>,
planetzoom <fo*@fox.orgwrote:
>给出以下代码：
>Given the following code:
> #include< stdio.h>
>#include <stdio.h>
> int main（void）
char array [100] ="什么是你最喜欢的车？" ;;
void * vp =& array;
printf（"％s \ n"，vp）;
返回0;
}
>int main(void)
{
char array[100] = "What is your favorite car?";
void *vp = &array;
printf("%s\n", vp);
return 0;
}
> printf（）语句是否正确？或者是vp所需的char * *
printf（"％s \ n"，（char *）vp）;
也就是说，假设void *指向一个字符串，打印字符串的正确方法是什么？
>Is the printf() statement correct? Or is a cast to char * required for vp?
printf("%s\n", (char *) vp);
That is, assuming a void * is pointing to a string, what is the proper way
to print the string?
void *需要具有与char *相同的表示形式，因此
理论上上述应该有效。 （但它冒犯了我的感情;-)
-
编程就是在你忙于制定其他计划的时候发生的事情。
void* is required to have the same representation as char*, so
in theory the above should work. (But it offends my sensibilities ;-) )
--
Programming is what happens while you''re busy making other plans.
planetzoom写道：
planetzoom wrote:
给出以下代码：
#include< ; stdio.h>
int main（无效）
{
char array [100] ="你的是什么最喜欢的车？" ;;
void * vp =& array;
printf（"％s \ n"，vp）;
返回0;
}
printf（）语句是否正确？或者是vp所需的char * *
printf（"％s \ n"，（char *）vp）;
Given the following code:
#include <stdio.h>
int main(void)
{
char array[100] = "What is your favorite car?";
void *vp = &array;
printf("%s\n", vp);
return 0;
}
Is the printf() statement correct? Or is a cast to char * required for vp?
printf("%s\n", (char *) vp);
在这种特殊情况下可能实际上并不需要演员表，
但是......
The cast is probably not actually required in this special case,
but...
也就是说，假设void *指向一个字符串，打印字符串的正确方法是什么？
？
That is, assuming a void * is pointing to a string, what is the proper way
to print the string?
....通常最好不要依赖任何两种不同的指针类型
以相同的方式传递。将vp转换为char *，你肯定不会遇到问题。
....it''s generally best not to rely on any two different pointer types
being passed the same way. Convert vp to char *, and you''re sure not
to run into problems.
ro ****** @ ibd.nrc-cnrc.gc.ca （Walter Roberson）在
news：eq ********** @ canopus.cc.umanitoba.ca:
ro******@ibd.nrc-cnrc.gc.ca (Walter Roberson) wrote in
news:eq**********@canopus.cc.umanitoba.ca:
文章< Xn * ***********************@207.217.125.201> ;,
planetzoom< fo*@fox.orgwrote：
In article <Xn************************@207.217.125.201>,
planetzoom <fo*@fox.orgwrote:
>>给出以下代码：
>>Given the following code:
>> #include< ; stdio.h中>
>>#include <stdio.h>
>> int main（void）
{char array [100] ="你最喜欢的是什么car？" ;;
void * vp =& array;
printf（"％s \ n"，vp）;
返回0;
}
>>int main(void)
{
char array[100] = "What is your favorite car?";
void *vp = &array;
printf("%s\n", vp);
return 0;
}
>> printf（）语句是否正确？或者是针对vp的char *需要
吗？ printf（"％s \ n"，（char *）vp）;
也就是说，假设void *指向一个字符串，打印字符串的正确方法是什么？
>>Is the printf() statement correct? Or is a cast to char * required
for vp? printf("%s\n", (char *) vp);
That is, assuming a void * is pointing to a string, what is the proper
way to print the string?
void *需要与char *具有相同的表示形式，因此
理论上应该有效。 （但它冒犯了我的感情;-)
）
void* is required to have the same representation as char*, so
in theory the above should work. (But it offends my sensibilities ;-)
)
好的，谢谢Walter和truedfx的解释。 :)
Ok, thank you Walter and truedfx for your explanations. :)
这篇关于void *等同于char *？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
