指针问题......最后一天？ :-) [英] Pointer question...last for the day? :-)
问题描述
有一件事困扰了我一段时间（好吧，不止一件事！）。
如果我有一个功能：
foo（char * s）{
char * t = s;
......
s ++; < ---几次任意时间
}
现在......我的问题是这个。
是t独立于s，意思是：
1）在s ++之后它仍然指向s的开头吗？
2）我想与1有关，如果我现在评价* t，它会是s中的第一个
字符吗？
谢谢......那是'它为今天!!!
One thing has puzzled me a while ( well, more than one thing!).
If I have a function:
foo( char *s){
char *t = s;
......
s++; <<--- a few arbitrary times
}
Now...my question is this.
Is "t" independent of s, in the sense of:
1) Will it still point to the beginning of s, after s++ ?
2) I guess related to 1, if I now evaluate *t, will it be the first
character in s?
Thanks...that''s it for today!!!
推荐答案
" mdh" < md ** @ comcast.netwrote in message
news：d8 **************************** ****** @ l17g2000 pri.googlegroups.com ...
"mdh" <md**@comcast.netwrote in message
news:d8**********************************@l17g2000 pri.googlegroups.com...
有一件事困扰了我一段时间（好吧，不止一件事！）。
如果我有一个功能：
foo（char * s）{
One thing has puzzled me a while ( well, more than one thing!).
If I have a function:
foo( char *s){
地址s的副本传递给foo。
A copy of the address s is passed to foo.
char * t = s;
char *t = s;
如果将复制的地址放入指针t，我们会存储一份副本。
We store a copy if the copied address into pointer t.
.....
s ++; < ---几次任意次
.....
s++; <<--- a few arbitrary times
我们将推送到函数中的地址的副本增加几个
时间。
We increment the copy of the address that was pushed into the function a few
times.
}
现在......我的问题是这个。
是t独立于s，意思是：
1）在s ++之后它还会指向s的开头吗？
}
Now...my question is this.
Is "t" independent of s, in the sense of:
1) Will it still point to the beginning of s, after s++ ?
当然。
Of course.
2）我想与1相关，如果我现在评估* t，它会成为s中的第一个
角色吗？
2) I guess related to 1, if I now evaluate *t, will it be the first
character in s?
我想K& R2第5章会有所帮助。
**发自 http://www.teranews.com **
I guess that K&R2 Chapter 5 will be helpful.
** Posted from http://www.teranews.com **
5月5日， 10:52 pm，mdh< m ... @ comcast.netwrote：
On May 5, 10:52 pm, mdh <m...@comcast.netwrote:
有一件事困扰了我一段时间（好吧，不止一件事！）。
如果我有一个功能：
foo（char * s）{
char * t = s;
.....
s ++; < ---几次任意时间
}
现在......我的问题是这个。
是t独立于s，意思是：
1）在s ++之后它仍然指向s的开头吗？
2）我想与1有关，如果我现在评价* t，它会是s中的第一个
字符吗？
谢谢......那是'它今天！
One thing has puzzled me a while ( well, more than one thing!).
If I have a function:
foo( char *s){
char *t = s;
.....
s++; <<--- a few arbitrary times
}
Now...my question is this.
Is "t" independent of s, in the sense of:
1) Will it still point to the beginning of s, after s++ ?
2) I guess related to 1, if I now evaluate *t, will it be the first
character in s?
Thanks...that''s it for today!!!
在尝试之前，有什么东西可以让你困惑
看看会发生什么？
-
Robert Gamble
How long does something have to puzzle you before you give it a try
and see what happens?
--
Robert Gamble
5月5日，7：59 * pm，Dann Corbit < dcor ... @ connx.comwrote：
On May 5, 7:59*pm, "Dann Corbit" <dcor...@connx.comwrote:
>
>
Ist独立于s，意思是：
Is "t" independent of s, in the sense of:
1）在s ++之后它还会指向s的开头吗？
1) Will it still point to the beginning of s, after s++ ?
当然。
Of course.
由于某种原因我有这个概念性概念，即当s增加时，它会导致t看到与s相同的原始数组部分。什么
你说的是，一旦新的指针被初始化，它会独立地运作
并可以这样使用？
For some reason I had this conceptual notion that as s is incremented,
it causes t to "see" the same part of the original array as s. What
you are saying is that once the new pointer is initialized, it acts
independently and can be used as such?
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