strtok导致分段错误 [英] strtok causes Segmentation fault
问题描述
我需要分隔一个字符串。分隔符是分号和逗号。
当我运行程序时，我在第一个strtok上出现了分段错误。
我按照其他人的例子和我的旧C书，但我不能...... b $ b似乎找到了问题。访问列表的格式为
20,45; 22,44; 46,28; 99,43等。我做错了什么？
谢谢，
#include< sys / signal.h>
#include< messages.h>
#include< stdio.h>
#include< string.h>
#include < stdlib.h>
#include< unistd.h>
#include< ctype.h>
#define或||
#define和&&
int createvarible（const int sock，char * name，char * type，char * value ，
char * list）
{
int n = 0，size，returnval = 0;
char * tokenptr = NULL，* tokenptr2 = NULL;
int accesscode，portnum;
tokenptr = strtok（list，" ;;"）; //这一行会导致seg错误为什么？
if（tokenptr == NULL）{
tokenptr2 = strtok（list，"，"） ; //分隔访问码，因为没有
分号
accesscode = atoi（tokenptr2）;
tokenptr2 = strtok（NULL，"， "）; //分隔端口
portnum = atoi（tokenptr2）;
printf（" code [0]％d \ n"，accesscode）;
printf（" port [0]％d \ n"，portnum）; }
else {
while（tokenptr！= NULL）{//不要担心这里的代码吧
做什么我需要
tokenptr2 = strtok（list，" ;;"）; //分隔访问码
accesscode = atoi（tokenptr2）;
tokenptr2 = strtok（NULL，"，"）; // delimit portnum
portnum = atoi（tokenptr2）;
printf（" code [0]％d \ n"，accesscode）;
printf（" port [0]％d \ n"，portnum）;
n ++;
}
}
返回访问码;
}
bo******@hotmail.com 写道：我需要分隔一个字符串。分隔符是分号和逗号。
当我运行程序时，我在第一个strtok上遇到了分段错误。
我按照其他人的例子和旧C书的例子，但我不能
似乎找到了问题。访问列表的格式为
20,45; 22,44; 46,28; 99,43等。我做错了什么？
谢谢，
#include< sys / signal.h>
#include< messages.h>
#include< stdio.h>
#include< string.h>
#include< stdlib.h>
#include< unistd.h>
#include < ctype.h>
#define或||
＃define和&
int createvarible（const int sock，char * name，char * type，char * value，
char * list）
{n / 0，size，returnval = 0;
char * tokenptr = NULL，* tokenptr2 = NULL;
int accesscode，portnum;
tokenptr = strtok（list，" ;;"）; //这一行会导致seg错误为什么？
首次用作strtok（）的arg时，列表是非空的吗？它是
是否空终止？
" void * clvrmnky（）" < CL ************** @ hotmail.com.invalid>在留言中写道
新闻：KE ****************** @ nnrp.ca.mci.com！nnrp1.uu net.ca ...bo******@hotmail.com 写道：我需要分隔一个字符串。分隔符是分号和逗号。
当我运行程序时，我在第一个strtok上遇到了分段错误。
我按照其他人的例子和旧C书的例子，但我不能
似乎找到了问题。访问列表的格式为
20,45; 22,44; 46,28; 99,43等。我做错了什么？
谢谢，
#include< sys / signal.h>
#include< messages.h>
#include< stdio.h>
#include< string.h>
#include< stdlib.h>
#include< unistd.h>
#include < ctype.h>
#define或||
＃define和&
int createvarible（const int sock，char * name，char * type，char * value，
char * list）
{n / 0，size，returnval = 0;
char * tokenptr = NULL，* tokenptr2 = NULL;
int accesscode，portnum;
tokenptr = strtok（list，" ;;"）; //这一行会导致seg错误为什么？
当第一个用作stgok（）的arg时，列表是非空的吗？它是否以空终止？
非标准的东西。这个问题是否已经被框架化，以便在clc中成为主题？ Joe
以下是我调用createvarible的方法：
createvarible（ss，" xyz"，" string"，"这是一个test，
" 22,43; 44,33"）
所以为了回答你的问题，字符串为空终止。要null
终止字符串我认为我必须把\0放在最右边？
谢谢，
I need to delimit a string. The delimiters are a semicolon and comma.
When I run the program I get a segmentation fault on the first strtok.
I followed the examples of others and from my old C books, but I can''t
seem to find the problem. The accesslist has a format of
20,45;22,44;46,28;99,43,etc. What am I doing wrong?
Thanks,
#include <sys/signal.h>
#include <messages.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <unistd.h>
#include <ctype.h>
#define or ||
#define and &&
int createvarible(const int sock, char *name, char *type, char *value,
char *list)
{
int n=0, size, returnval=0;
char *tokenptr=NULL, *tokenptr2=NULL;
int accesscode, portnum;
tokenptr = strtok(list, ";"); //this line causes the seg fault WHY?
if (tokenptr == NULL) {
tokenptr2 = strtok(list, ",");//delimit accesscode as there is no
semicolon
accesscode=atoi(tokenptr2);
tokenptr2 = strtok(NULL, ",");//delimit port
portnum=atoi(tokenptr2);
printf("code[0] %d\n", accesscode);
printf("port[0] %d\n", portnum); }
else {
while (tokenptr != NULL) { //don''t worry about the code down here it
does what I need
tokenptr2 = strtok(list, ";");//delimit accesscode
accesscode=atoi(tokenptr2);
tokenptr2 = strtok(NULL, ",");//delimit portnum
portnum=atoi(tokenptr2);
printf("code[0] %d\n",accesscode);
printf("port[0] %d\n",portnum);
n++;
}
}
return accesscode;
}
bo******@hotmail.com wrote:I need to delimit a string. The delimiters are a semicolon and comma.
When I run the program I get a segmentation fault on the first strtok.
I followed the examples of others and from my old C books, but I can''t
seem to find the problem. The accesslist has a format of
20,45;22,44;46,28;99,43,etc. What am I doing wrong?
Thanks,
#include <sys/signal.h>
#include <messages.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <unistd.h>
#include <ctype.h>
#define or ||
#define and &&
int createvarible(const int sock, char *name, char *type, char *value,
char *list)
{
int n=0, size, returnval=0;
char *tokenptr=NULL, *tokenptr2=NULL;
int accesscode, portnum;
tokenptr = strtok(list, ";"); //this line causes the seg fault WHY?
Is list non-null when first used as an arg to strtok()? Is it
null-terminated?
"void * clvrmnky()" <cl**************@hotmail.com.invalid> wrote in message
news:KE******************@nnrp.ca.mci.com!nnrp1.uu net.ca...bo******@hotmail.com wrote:I need to delimit a string. The delimiters are a semicolon and comma.
When I run the program I get a segmentation fault on the first strtok.
I followed the examples of others and from my old C books, but I can''t
seem to find the problem. The accesslist has a format of
20,45;22,44;46,28;99,43,etc. What am I doing wrong?
Thanks,
#include <sys/signal.h>
#include <messages.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <unistd.h>
#include <ctype.h>
#define or ||
#define and &&
int createvarible(const int sock, char *name, char *type, char *value,
char *list)
{
int n=0, size, returnval=0;
char *tokenptr=NULL, *tokenptr2=NULL;
int accesscode, portnum;
tokenptr = strtok(list, ";"); //this line causes the seg fault WHY?
Is list non-null when first used as an arg to strtok()? Is it
null-terminated?
Non Standard stuff. Could this question have been framed so as to be
topical in clc? Joe
Here is how I call createvarible:
createvarible(ss, "xyz", "string", "this is a test",
"22,43;44,33")
So to answer your question the string is null terminated. To null
terminate the string I think I have to put \0 at the end right?
Thanks,
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