endl错误（极端新手） [英] endl error (extreme novice)
问题描述
我正在处理我的第二个程序，所以请耐心等待。
当我尝试编译它时，我收到两条错误消息（3种类型）：
函数`int main（）''：
第6行：`endl''未声明（首先使用此函数）
第8行`end' '未声明（首先使用此功能）
我正在使用一个名为Dev-C ++的编译器，所以如果有人知道更好的编译器，我就是b $ b am接受推荐。
谢谢，
这是我目前的计划：
#include< iostream> ;
int main（）
{
int x = 5;
int y = 7;
std :: cout<< endl;
std :: cout<< x + y<< " " << x * y;
std :: cout<<结束;
返回0;
}
#include< ;&的iostream GT;
int main（）
{
int x = 5;
int y = 7;
std :: cout<< endl;
std :: cout<< x + y<< " " << x * y;
std :: cout<<结束;
返回0;
}
endl是（就像cout一样）在std的范围内。
所以你必须把std ::放在它之前。
你可以选择在#include< iostream>
之后使用这一行namespace std;
它将声明std作为标准命名空间
Jd ****** @ gmail。 com 写道：
我正在处理我的第二个程序，所以请耐心等待。
当我尝试编译时它，我收到两条错误消息（有点3）：
函数`int main（）''：
第6行：`endl''未声明（首先使用此功能）
第8行结束未声明（首次使用此功能）
我正在使用名为Dev-的编译器C ++，所以如果有人知道一个更好的，我可以接受建议。
Dev-C ++是环境。我记得，它使用的编译器是g ++
并且它没有任何问题。
谢谢你，
>这是我当前的程序：
#include< iostream>
你知道上面那行吗？
int main（）
{
int x = 5;
int y = 7;
std :: cout<< ENDL;
你知道为什么你在cout前写了std ::。使用endl执行相同的
，即将endl更改为std :: endl，你的问题将会消失，但你知道为什么吗？
std :: cout<< x + y<< " " << x * y;
作为附带问题，您确定该行是否正确？当你得到
程序时，输出是你想要的吗？
std :: cout<<结束;
endl已经结束。我希望你不是那个意思。
返回0;
}
你从哪里学习C ++并不能解释这个？一本书？或者是一个
的网站？因为代码中的错误，正确地将std :: in
前面的一个名称（cout）但错误地从另一个名称中删除了
（endl），这是一个奇怪的一本书或一本不错的网络教程（其中很少有b
）。
你有没有任何其他语言的编程经验C ++？如果
如此，则 http://www.acceleratedcpp.com/ 是一本很棒的书，教你
C ++编程。但它确实假设了一些以前的，非C ++，
的体验。
Gavin Deane
Jd******@gmail.com 写道：
< blockquote class =post_quotes>
我正在处理我的第二个程序，所以请耐心等待。
当我尝试编译它时，我收到两条错误消息（3种） ：
函数`int main（）''：
第6行：`endl''未声明（首先使用此函数）
第8行结束未声明（首次使用此功能）
我正在使用名为Dev-C ++的编译器，所以如果有人知道更好的编译器，我
对建议持开放态度。
Dev-C ++是环境。我记得，它使用的编译器是g ++
并且它没有任何问题。
谢谢你，
>这是我当前的程序：
#include< iostream>
你知道上面那行吗？
int main（）
{
int x = 5;
int y = 7;
std :: cout<< ENDL;
你知道为什么你在cout前写了std ::。使用endl执行相同的
，即将endl更改为std :: endl，你的问题将会消失，但你知道为什么吗？
std :: cout<< x + y<< " " << x * y;
作为附带问题，您确定该行是否正确？当你得到
程序时，输出是你想要的吗？
std :: cout<<结束;
endl已经结束。我希望你不是那个意思。
返回0;
}
你从哪里学习C ++并不能解释这个？一本书？或者是一个
的网站？因为代码中的错误，正确地将std :: in
前面的一个名称（cout）但错误地从另一个名称中删除了
（endl），这是一个奇怪的一本书或一本不错的网络教程（其中很少有b
）。
你有没有任何其他语言的编程经验C ++？如果
如此，则 http://www.acceleratedcpp.com/ 是一本很棒的书，教你
C ++编程。但它确实假设了一些以前的，非C ++，
的体验。
Gavin Deane
I am working on my second program ever, so bear with me.
When I try to compile it, I get two error messages(sort of 3):
In function `int main()'':
line 6: `endl'' undeclared (first use this function)
line 8 `end'' undeclared (first use this function)
I''m using a compiler called Dev-C++, so if anyone knows a better one, I
am open to recommendations.
Thank you,
Here is my current program:
#include <iostream>
int main()
{
int x = 5;
int y = 7;
std::cout << endl;
std::cout << x + y << " " << x * y;
std::cout << end;
return 0;
}
#include <iostream>int main()
{
int x = 5;
int y = 7;
std::cout << endl;
std::cout << x + y << " " << x * y;
std::cout << end;
return 0;
}endl is(just as cout) within the scope of std.
so you have to put std:: before it.
you can alternatively put this line after #include <iostream>
using namespace std;
it will declare "std" as the "standard" namespace
Jd******@gmail.com wrote:I am working on my second program ever, so bear with me.
When I try to compile it, I get two error messages(sort of 3):
In function `int main()'':
line 6: `endl'' undeclared (first use this function)
line 8 `end'' undeclared (first use this function)
I''m using a compiler called Dev-C++, so if anyone knows a better one, I
am open to recommendations.Dev-C++ is the environment. As I recall, the compiler it uses is g++
and there''s nothing wrong with it.
Thank you,>Here is my current program:
#include <iostream>Do you know what that line above does?
int main()
{
int x = 5;
int y = 7;
std::cout << endl;Do you know why you have written std:: in front of cout. Do the same
with endl, i.e. change endl to std::endl, and your problem will go
away, but do you know why?
std::cout << x + y << " " << x * y;As a side issue, are you sure that line is correct? When you get the
program working, is the output what you intended?
std::cout << end;endl has become end. I expect you didn''t mean that.
return 0;
}Where are you learning C++ from that doesn''t explain this? A book? Or a
website? Because the error in your code, correctly putting std:: in
front of one name (cout) but incorrectly leaving it off another name
(endl), is a strange one for a book or a decent web tutorial (of which
there are very few) to make.
Have you got any programming experience in languages other than C++? If
so, then http://www.acceleratedcpp.com/ is a superb book to teach you
C++ programming. But it does presume some previous, non-C++,
experience.
Gavin Deane
Jd******@gmail.com wrote:I am working on my second program ever, so bear with me.
When I try to compile it, I get two error messages(sort of 3):
In function `int main()'':
line 6: `endl'' undeclared (first use this function)
line 8 `end'' undeclared (first use this function)
I''m using a compiler called Dev-C++, so if anyone knows a better one, I
am open to recommendations.Dev-C++ is the environment. As I recall, the compiler it uses is g++
and there''s nothing wrong with it.
Thank you,>Here is my current program:
#include <iostream>Do you know what that line above does?
int main()
{
int x = 5;
int y = 7;
std::cout << endl;Do you know why you have written std:: in front of cout. Do the same
with endl, i.e. change endl to std::endl, and your problem will go
away, but do you know why?
std::cout << x + y << " " << x * y;As a side issue, are you sure that line is correct? When you get the
program working, is the output what you intended?
std::cout << end;endl has become end. I expect you didn''t mean that.
return 0;
}Where are you learning C++ from that doesn''t explain this? A book? Or a
website? Because the error in your code, correctly putting std:: in
front of one name (cout) but incorrectly leaving it off another name
(endl), is a strange one for a book or a decent web tutorial (of which
there are very few) to make.
Have you got any programming experience in languages other than C++? If
so, then http://www.acceleratedcpp.com/ is a superb book to teach you
C++ programming. But it does presume some previous, non-C++,
experience.
Gavin Deane
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